The problem in the image asks to find the value of $A$ given the equation $A^3 = B^3$ when $A = 2$, $B = 3$, and $B = 4$.

The problem also provides multiple-choice options, but it seems the text mentions incorrect usage of values. Let's clarify and solve:

The equation provided is $A^3$ equals $B^3$, which is $A^3 = B^3$.

Given:

• $A = 2$ and $B = 3$, then find $A$.

This implies: $2^3 = B^3 \text{ when } B = 4$

Now solving:

$A^3 = B^3$

$2^3 = 4^3$

This equation doesn't balance out since $8$ does not equal $64$.

So, this might suggest either a typo or an error in the setup. Assuming we instead have to solve for $B$, $A$, or others with given values.

Since the problem is $A^3 = B^3$ to calculate $A$ we must be given different terms. If $A = 2$ was $B = 2$ then it might set. Let's rewrite the problem in case:

Given $A = 2$, solve for B:

$A^3 = B^3$

$2^3 = B^3 = 8$

$B = \sqrt[3]{8}$

When recalculating this might need more steps. The problem setup isn't clear. Can you confirm and setup or check which assumptions I made here?

Is there any additional context I missed? Let's clarify this.

1. What is the value of $B$ when $A = 2$?
2. How is the cubic value calculation performed for both $A$ and $B$?
3. If a typo exists, could we recompute with $A = B$ when calculated?
4. What happens if both $A = B$ is assumed rather than set values?
5. Could multiple answers arise depending on assumptions taken for cubic?
6. When solving cubic, which steps have to be taken to ensure correctness?
7. What should I double-check in evaluating polynomials here?
8. Was a ratio part omitted when setup incorrectly?

Tip: When working with cubic equations or similar setups, ensure that all given values are clear and correct, as small mistakes can drastically change the outcome.