2.The label on a box of cereal gives the mass of cereal in two units: 978 grams and 34.5 oz. Use this information to find a conversion factor between the English and metric units. 3.Soccer is played with a round ball having a circumference between 27 and 28 inches and a mass between 14 and 16 oz. What are these specifications in cm and g? 4.A barrel of oil is exactly 42 gal. How many liters of oil are in the barrel? 5.ls a 197-|b weight lifter light enough to compete in a class limited to those weighing 90 kg or less?

Let's tackle each problem one by one.

### Problem 2: Conversion Factor Between Grams and Ounces

Given:
- Mass of cereal: 978 grams (g) = 34.5 ounces (oz)

We can find the conversion factor by dividing the two masses:

\[
\text{Conversion factor} = \frac{978 \text{ g}}{34.5 \text{ oz}} \approx 28.35 \text{ g/oz}
\]

So, the conversion factor is approximately **28.35 grams per ounce**.

### Problem 3: Soccer Ball Specifications in Metric Units

1. **Circumference Conversion (Inches to Centimeters):**

   The circumference is between 27 and 28 inches. To convert inches to centimeters, use the conversion factor \(1 \text{ inch} = 2.54 \text{ cm}\).

   \[
   27 \text{ inches} \times 2.54 \text{ cm/inch} = 68.58 \text{ cm}
   \]
   \[
   28 \text{ inches} \times 2.54 \text{ cm/inch} = 71.12 \text{ cm}
   \]

   So, the circumference is between **68.58 cm** and **71.12 cm**.

2. **Mass Conversion (Ounces to Grams):**

   The mass is between 14 and 16 ounces. Using the conversion factor from Problem 2 (28.35 g/oz):

   \[
   14 \text{ oz} \times 28.35 \text{ g/oz} = 396.9 \text{ g}
   \]
   \[
   16 \text{ oz} \times 28.35 \text{ g/oz} = 453.6 \text{ g}
   \]

   So, the mass is between **396.9 g** and **453.6 g**.

### Problem 4: Volume of Oil in Liters

Given:
- 1 barrel of oil = 42 gallons (gal)
- Conversion factor: \(1 \text{ gallon} = 3.785 \text{ liters}\)

\[
42 \text{ gal} \times 3.785 \text{ liters/gal} = 158.97 \text{ liters}
\]

So, the volume of oil in the barrel is approximately **158.97 liters**.

### Problem 5: Weight Class Conversion

Given:
- Weight of the lifter: 197 lb
- Conversion factor: \(1 \text{ lb} = 0.4536 \text{ kg}\)

\[
197 \text{ lb} \times 0.4536 \text{ kg/lb} = 89.36 \text{ kg}
\]

Since 89.36 kg is less than 90 kg, the lifter is **light enough** to compete in the class limited to those weighing 90 kg or less.

### Follow-up Questions:
1. How do you convert mass from kilograms to pounds?
2. What is the volume of a liter in cubic centimeters?
3. How would you convert square inches to square centimeters?
4. What is the importance of knowing conversion factors in everyday situations?
5. If a different cereal box had 500 grams, how many ounces would that be?

**Tip:** Understanding conversion factors can simplify calculations and allow you to switch between different measurement systems effortlessly, which is particularly useful in international contexts.

Explore how to solve conversion problems involving cereal mass in grams and ounces, soccer ball specifications in centimeters and grams, and oil volume in liters. Understand unit conversion formulas and their practical applications. Suitable for students in Grades 7-9.

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