Math Problem Statement

Solve

Solve the complex number expressions provided in the image.

Solution

Here are the solutions for the first set of problems from your image (complex number multiplication):

  1. 8(2i)(54i)8(-2i)(-5 - 4i)

    • Simplified: 16i(54i)=80i64=64+80i-16i(-5 - 4i) = -80i - 64 = -64 + 80i
  2. (22i)2(2 - 2i)^2

    • This expression can be expanded to (22i)(22i)=8i(2 - 2i)(2 - 2i) = 8i
  3. (4i)(2i)(8+4i)(4i)(-2i)(-8 + 4i)

    • Simplified: (4i)(2i)(8+4i)=64+32i(4i)(-2i)(-8 + 4i) = -64 + 32i
  4. (44i)(13i)(-4 - 4i)(1 - 3i)

    • Expanding: (44i)(13i)=168i(-4 - 4i)(1 - 3i) = -16 - 8i
  5. (72i)(64i)(7 - 2i)(6 - 4i)

    • Simplified to: 5034i50 - 34i
  6. (43i)(66i)(4 - 3i)(6 - 6i)

    • Expanded: 4218i42 - 18i

Would you like detailed steps for each? Let me know!

Here are some related questions you could explore:

  1. What is the general process for multiplying complex numbers?
  2. How can we simplify expressions with powers of ii?
  3. What are the steps to divide complex numbers?
  4. How does multiplying conjugates simplify complex expressions?
  5. How can we express a complex number in polar form?

Tip: Always simplify powers of ii as i2=1i^2 = -1.

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Math Problem Analysis

Mathematical Concepts

Complex Numbers
Multiplication of Complex Numbers
Division of Complex Numbers

Formulas

Multiplication of Complex Numbers: (a + bi)(c + di) = (ac - bd) + (ad + bc)i
Division of Complex Numbers: (a + bi) / (c + di) = [(a + bi)(c - di)] / (c^2 + d^2)

Theorems

Complex Number Multiplication Theorem
Conjugate Method for Division of Complex Numbers

Suitable Grade Level

Grades 10-12