Math Problem Statement

explain me dividing and multiplicating complex numbers

Solution

Multiplying and Dividing Complex Numbers

1. Complex Numbers Recap:

A complex number is written in the form z=a+biz = a + bi, where:

  • aa is the real part
  • bb is the imaginary part
  • ii is the imaginary unit, defined by i2=1i^2 = -1

2. Multiplying Complex Numbers:

When multiplying two complex numbers, we apply the distributive property (FOIL method, like multiplying binomials) and simplify the terms.

Let’s multiply two complex numbers: z1=a+biz_1 = a + bi and z2=c+diz_2 = c + di.

z1z2=(a+bi)(c+di)z_1 \cdot z_2 = (a + bi)(c + di)

Using the distributive property:

z1z2=a(c+di)+bi(c+di)z_1 \cdot z_2 = a(c + di) + bi(c + di)

Expanding each term:

=ac+adi+bci+bdi2= ac + adi + bci + bdi^2

Since i2=1i^2 = -1:

=ac+adi+bcibd= ac + adi + bci - bd

Now group real and imaginary parts:

=(acbd)+(ad+bc)i= (ac - bd) + (ad + bc)i

So, the product of two complex numbers z1z_1 and z2z_2 is:

z1z2=(acbd)+(ad+bc)iz_1 \cdot z_2 = (ac - bd) + (ad + bc)i

3. Dividing Complex Numbers:

Dividing complex numbers involves multiplying both the numerator and denominator by the conjugate of the denominator to eliminate the imaginary part in the denominator.

Let’s divide z1=a+biz_1 = a + bi by z2=c+diz_2 = c + di.

z1z2=a+bic+di\frac{z_1}{z_2} = \frac{a + bi}{c + di}

Step 1: Multiply the numerator and denominator by the conjugate of z2z_2, which is cdic - di.

a+bic+dicdicdi=(a+bi)(cdi)(c+di)(cdi)\frac{a + bi}{c + di} \cdot \frac{c - di}{c - di} = \frac{(a + bi)(c - di)}{(c + di)(c - di)}

Step 2: Multiply both the numerator and denominator.

For the denominator: (c+di)(cdi)=c2(di)2=c2d2i2=c2+d2(c + di)(c - di) = c^2 - (di)^2 = c^2 - d^2 i^2 = c^2 + d^2

For the numerator: (a+bi)(cdi)=acadi+bcibdi2=(ac+bd)+(bcad)i(a + bi)(c - di) = ac - adi + bci - bdi^2 = (ac + bd) + (bc - ad)i

So the division is:

z1z2=(ac+bd)+(bcad)ic2+d2\frac{z_1}{z_2} = \frac{(ac + bd) + (bc - ad)i}{c^2 + d^2}

This gives the real and imaginary parts of the result.

4. Summary of Formulas:

  • Multiplication: (a+bi)(c+di)=(acbd)+(ad+bc)i(a + bi)(c + di) = (ac - bd) + (ad + bc)i
  • Division: a+bic+di=(ac+bd)+(bcad)ic2+d2\frac{a + bi}{c + di} = \frac{(ac + bd) + (bc - ad)i}{c^2 + d^2}

Would you like further details or examples on this topic?


5 Relative Questions:

  1. Can you explain the geometric interpretation of multiplying complex numbers?
  2. How do polar forms of complex numbers simplify multiplication and division?
  3. How does the magnitude of a complex number affect multiplication?
  4. What is the result of dividing a complex number by a real number?
  5. How does the conjugate of a complex number assist in division?

Tip: Multiplying complex numbers can rotate vectors in the complex plane, and division can reverse or adjust this rotation.

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Math Problem Analysis

Mathematical Concepts

Complex Numbers
Algebra

Formulas

Multiplication: (a + bi)(c + di) = (ac - bd) + (ad + bc)i
Division: \frac{a + bi}{c + di} = \frac{(ac + bd) + (bc - ad)i}{c^2 + d^2}

Theorems

Complex Conjugate Theorem
Distributive Property

Suitable Grade Level

Grades 10-12