Math Problem Statement

Simplify the following expressions: a. (4 + i)/(7 + i) b. (12 + 6i) + (9 + 5i)

Solution

Let's simplify the given expressions:

a. 4+i7+i\frac{4 + i}{7 + i}

To simplify this complex fraction, multiply both the numerator and the denominator by the conjugate of the denominator. The conjugate of 7+i7 + i is 7i7 - i.

4+i7+i×7i7i=(4+i)(7i)(7+i)(7i)\frac{4 + i}{7 + i} \times \frac{7 - i}{7 - i} = \frac{(4 + i)(7 - i)}{(7 + i)(7 - i)}

First, simplify the denominator:

(7+i)(7i)=72i2=49(1)=50(7 + i)(7 - i) = 7^2 - i^2 = 49 - (-1) = 50

Now, expand the numerator:

(4+i)(7i)=4×74×i+i×7i×i=284i+7ii2(4 + i)(7 - i) = 4 \times 7 - 4 \times i + i \times 7 - i \times i = 28 - 4i + 7i - i^2

Simplify the expression:

=28+3i+1=29+3i= 28 + 3i + 1 = 29 + 3i

So, the simplified form is:

4+i7+i=29+3i50=2950+3i50\frac{4 + i}{7 + i} = \frac{29 + 3i}{50} = \frac{29}{50} + \frac{3i}{50}

b. (12+6i)+(9+5i)(12 + 6i) + (9 + 5i)

To simplify this expression, just add the real parts and the imaginary parts separately:

(12+6i)+(9+5i)=(12+9)+(6i+5i)=21+11i(12 + 6i) + (9 + 5i) = (12 + 9) + (6i + 5i) = 21 + 11i

So the simplified expression is:

21+11i21 + 11i


Would you like more details or have any questions? Here are some related problems for practice:

  1. Simplify 3+2i43i\frac{3 + 2i}{4 - 3i}.
  2. Add (8+2i)+(53i)(8 + 2i) + (5 - 3i).
  3. Simplify 54i2+3i\frac{5 - 4i}{2 + 3i}.
  4. Subtract (7+9i)(3+2i)(7 + 9i) - (3 + 2i).
  5. Multiply (2+3i)(4i)(2 + 3i)(4 - i).

Tip: When dealing with complex numbers, always remember to simplify the denominator by multiplying by the conjugate to eliminate the imaginary part in the denominator.

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Math Problem Analysis

Mathematical Concepts

Complex Numbers
Algebra

Formulas

(a + bi)(c - di) = (ac + bd) + (bc - ad)i
(a + bi) + (c + di) = (a + c) + (b + d)i

Theorems

Complex Conjugate

Suitable Grade Level

Grades 9-12