9x−3/−6=−79x−3−6=−7

x=x=

−3=−8x−10−10−3=−8x−10/−10

x=x=

3/5y−2=435y−2=4

y=y=

It looks like you have provided a series of algebraic equations that need to be solved. I'll solve them step by step.

### Equation 1:
\[
9x - \frac{3}{-6} = -7
\]

The fraction \(\frac{-3}{-6}\) simplifies to \(\frac{1}{2}\), so the equation becomes:

\[
9x + \frac{1}{2} = -7
\]

Next, subtract \(\frac{1}{2}\) from both sides:

\[
9x = -7 - \frac{1}{2}
\]

This simplifies to:

\[
9x = -\frac{14}{2} - \frac{1}{2} = -\frac{15}{2}
\]

Now divide both sides by 9:

\[
x = \frac{-15}{2 \cdot 9} = \frac{-15}{18} = -\frac{5}{6}
\]

So:
\[
x = -\frac{5}{6}
\]

---

### Equation 2:
\[
-3 = -8x - 10
\]

First, add 10 to both sides:

\[
-3 + 10 = -8x
\]

This simplifies to:

\[
7 = -8x
\]

Now divide both sides by -8:

\[
x = \frac{7}{-8} = -\frac{7}{8}
\]

So:
\[
x = -\frac{7}{8}
\]

---

### Equation 3:
\[
\frac{3}{5}y - 2 = 4
\]

Add 2 to both sides:

\[
\frac{3}{5}y = 4 + 2
\]

Simplifying:

\[
\frac{3}{5}y = 6
\]

Multiply both sides by \(\frac{5}{3}\):

\[
y = 6 \cdot \frac{5}{3} = \frac{30}{3} = 10
\]

So:
\[
y = 10
\]

---

### Final Answers:
1. \( x = -\frac{5}{6} \)
2. \( x = -\frac{7}{8} \)
3. \( y = 10 \)

Would you like any further details or explanations?

Here are five related questions:
1. How do you handle equations with fractions?
2. How would you solve the equation if decimals were involved?
3. What is the process for solving systems of equations?
4. How do you check if a solution is correct?
5. How do negative signs affect the operations in algebra?

**Tip:** Always simplify fractions or constants early to make the equation easier to work with.

9x−3/−6=−79x−3−6=−7; −3=−8x−10−10−3=−8x−10/−10; 3/5y−2=435y−2=4

Discover how to solve algebraic equations like 9x - 3/-6 = -7 and 3/5y - 2 = 4, including fraction simplifications and inverse operations. This detailed solution is suitable for students in Grades 8-10.

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