To solve the system of equations:

1. $y = 6 - 3x$
2. $2x + y = 5$

We can use the substitution method.

First, substitute the expression for $y$ from the first equation into the second equation:

$2x + (6 - 3x) = 5$

Now, simplify and solve for $x$:

$2x + 6 - 3x = 5$

$-x + 6 = 5$

$-x = 5 - 6$

$-x = -1$

$x = 1$

Now, substitute $x = 1$ back into the first equation to solve for $y$:

$y = 6 - 3(1)$

$y = 6 - 3$

$y = 3$

So, the solution to the system of equations is $x = 1$ and $y = 3$.

Would you like more details or have any questions about this solution? Here are some more questions you can ask:

1. Can you explain how to solve a different system of equations?
2. How do you solve a quadratic equation?
3. What is the method for solving inequalities?
4. Can you explain how to graph linear equations?
5. How do you solve a system of equations using the elimination method?

Tip: Always check your solution by substituting the values back into the original equations to ensure they satisfy both equations.