To solve the system of equations:

1. \( y = 6 - 3x \)
2. \( 2x + y = 5 \)

We can use the substitution method. 

First, substitute the expression for \( y \) from the first equation into the second equation:

\[ 2x + (6 - 3x) = 5 \]

Now, simplify and solve for \( x \):

\[ 2x + 6 - 3x = 5 \]

\[ -x + 6 = 5 \]

\[ -x = 5 - 6 \]

\[ -x = -1 \]

\[ x = 1 \]

Now, substitute \( x = 1 \) back into the first equation to solve for \( y \):

\[ y = 6 - 3(1) \]

\[ y = 6 - 3 \]

\[ y = 3 \]

So, the solution to the system of equations is \( x = 1 \) and \( y = 3 \).

Would you like more details or have any questions about this solution? Here are some more questions you can ask:

1. Can you explain how to solve a different system of equations?
2. How do you solve a quadratic equation?
3. What is the method for solving inequalities?
4. Can you explain how to graph linear equations?
5. How do you solve a system of equations using the elimination method?

**Tip:** Always check your solution by substituting the values back into the original equations to ensure they satisfy both equations.

Learn how to solve the system of equations y = 6 - 3x and 2x + y = 5 using the substitution method. Step-by-step solution provided with detailed calculations and verification. Suitable for high school level students.

Math Problem Statement

Solution

Ask a new question for Free

By Image

Math Problem Analysis

Mathematical Concepts

Formulas

Theorems

Suitable Grade Level

Related Recommendation