The equation you provided is $y = 2 - 3x$. This is a linear equation in the form $y = mx + b$, where $m$ is the slope and $b$ is the y-intercept. Here, the slope $m$ is -3, and the y-intercept $b$ is 2.

Analysis:

1. Slope (m): The slope of the line is -3. This means that for every unit increase in $x$, $y$ decreases by 3 units.
2. Y-intercept (b): The y-intercept is 2. This is the point where the line crosses the y-axis, at $(0, 2)$.

Graphing:

To graph this line, you can start at the y-intercept (0, 2). From there, use the slope to find another point on the line. Since the slope is -3, you can go down 3 units and to the right 1 unit to find another point.

Example Points:

• When $x = 0$, $y = 2$.
• When $x = 1$, $y = 2 - 3(1) = -1$.
• When $x = -1$, $y = 2 - 3(-1) = 5$.

Would you like to see a graph of this equation or have any specific questions about it?

Here are some questions you might find interesting to explore:

1. How do you determine the slope of a line from its equation?
2. What are the steps to graph a linear equation?
3. How can you find the x-intercept of this line?
4. What happens to the graph if the slope is changed to a positive value?
5. How do you solve for $x$ when given a specific $y$ value?