Math Problem Statement

Richard and Teo have a combined age of 26. Richard is 8 years older than twice Teo's age. How old are Richard and Teo?

Solution

Let's define variables:
Let TT be Teo's age and RR be Richard's age.

From the problem, we have two equations:

  1. R+T=26R + T = 26 (Their combined age is 26)
  2. R=2T+8R = 2T + 8 (Richard is 8 years older than twice Teo's age)

Solving the equations:

Substituting equation (2) into equation (1):

(2T+8)+T=26(2T + 8) + T = 26

3T+8=263T + 8 = 26

3T=183T = 18

T=6T = 6

Substituting T=6T = 6 into equation (2):

R=2(6)+8=12+8=20R = 2(6) + 8 = 12 + 8 = 20

Final Answer:

Richard is 20 years old, and Teo is 6 years old.

Would you like a step-by-step breakdown or further clarification?

Here are five related questions to expand your understanding:

  1. What would their ages be if their combined age was 30 instead?
  2. How would the equations change if Richard was 10 years older than twice Teo’s age?
  3. Can we solve this using a graphical method?
  4. What happens if Teo’s age is represented as xx and Richard’s age in terms of xx?
  5. How do you verify that your solution is correct?

Tip: When solving word problems, always define variables clearly and set up equations carefully before solving!

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Math Problem Analysis

Mathematical Concepts

Algebra
Linear Equations

Formulas

R + T = 26
R = 2T + 8

Theorems

Solving systems of linear equations

Suitable Grade Level

Grades 6-8