Math Problem Statement

Derivatives and trigonometric functions problems: y = sin^2(3x - 4), y = (cos 2x) / (3x - 4), y = (1/2) * tan(x * sin(2x)), Find y'' - 2y' when y = sin(3x) - cos(3x), Solve xy + 2x - 5y - y^2 = 0, Differentiate y = sin^2(x^2 - x) using chain rule, Find dy/dx for xy^2 + y - x^2 = 6.

Solution

The image you uploaded contains a series of mathematical problems involving derivatives, trigonometric functions, implicit differentiation, and chain rule applications. Here’s a breakdown of the problems and an approach to solving each:

  1. y=sin2(3x4)y = \sin^2(3x - 4)

    • Differentiate yy with respect to xx, using the chain rule.
  2. y=cos2x3x4y = \frac{\cos 2x}{3x - 4}

    • Use the quotient rule to differentiate this expression.
  3. y=12tan(xsin2x)y = \frac{1}{2} \tan (x \sin 2x)

    • Apply the chain rule to differentiate this function, considering both the tangent and sine functions.
  4. Find y2yy'' - 2y' when y=sin3xcos3xy = \sin 3x - \cos 3x.

    • First, compute the first and second derivatives of yy and then substitute into the given expression.
  5. xy+2x5yy2=0xy + 2x - 5y - y^2 = 0

    • Use implicit differentiation to find dydx\frac{dy}{dx}.
  6. y=sin2(x2x)y = \sin^2(x^2 - x)

    • Differentiate using the chain rule.
  7. Find dydx\frac{dy}{dx} from the equation xy2+yx2=6xy^2 + y - x^2 = 6.

    • Again, use implicit differentiation to find dydx\frac{dy}{dx}.

Would you like a step-by-step solution to any of these problems? Let me know which one you'd like to start with, and I'll guide you through it!


Here are 5 questions to expand on the information:

  1. How do you apply the chain rule in problem 1 to find the derivative of sin2(3x4)\sin^2(3x - 4)?
  2. What is the quotient rule and how is it applied in problem 2?
  3. Can you differentiate a composite function like in problem 3? How would you use the chain rule?
  4. What is implicit differentiation and how would you apply it to problem 5?
  5. In problem 7, how do you differentiate both sides of an equation like xy2+yx2=6xy^2 + y - x^2 = 6?

Tip: When performing implicit differentiation, always remember to apply the product rule where necessary (for example, with terms like xyxy).

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Math Problem Analysis

Mathematical Concepts

Derivatives
Trigonometric Functions
Implicit Differentiation
Chain Rule
Quotient Rule

Formulas

Chain Rule: dy/dx = dy/du * du/dx
Quotient Rule: (u/v)' = (u'v - uv') / v^2
Product Rule: (uv)' = u'v + uv'

Theorems

Implicit Differentiation
Chain Rule
Quotient Rule

Suitable Grade Level

Grades 11-12