Math Problem Statement

|x_1 |+2|x_2 |=8

Solution

The given equation is:

x1+2x2=8|x_1| + 2|x_2| = 8

Step 1: Consider Different Cases for Absolute Values

Since we have absolute values, we need to analyze all possible cases for x1x_1 and x2x_2:

  1. Case 1: x10x_1 \geq 0 and x20x_2 \geq 0
    x1+2x2=8x_1 + 2x_2 = 8

  2. Case 2: x10x_1 \geq 0 and x20x_2 \leq 0
    x1+2(x2)=8x12x2=8x_1 + 2(-x_2) = 8 \quad \Rightarrow \quad x_1 - 2x_2 = 8

  3. Case 3: x10x_1 \leq 0 and x20x_2 \geq 0
    (x1)+2x2=8x1+2x2=8(-x_1) + 2x_2 = 8 \quad \Rightarrow \quad -x_1 + 2x_2 = 8

  4. Case 4: x10x_1 \leq 0 and x20x_2 \leq 0
    (x1)+2(x2)=8x12x2=8(-x_1) + 2(-x_2) = 8 \quad \Rightarrow \quad -x_1 - 2x_2 = 8

Step 2: Analyze Solutions

Each of these cases represents a linear equation that describes a region in the (x1,x2)(x_1, x_2) plane. The solution set consists of all points that satisfy at least one of these equations.

Would you like me to solve for specific values of x1x_1 or x2x_2, or would you like a graphical representation of the solution set?


Here are five related questions to expand your understanding:

  1. How do absolute value equations affect the solution sets geometrically?
  2. Can this equation represent a bounded region in the coordinate plane?
  3. How would the solution change if the equation were x1+2x28|x_1| + 2|x_2| \leq 8?
  4. What is the relationship between absolute value equations and piecewise functions?
  5. How can we extend this concept to higher dimensions?

Tip: Always break absolute value equations into separate cases and solve each one carefully to ensure you capture all solutions.

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Math Problem Analysis

Mathematical Concepts

Algebra
Absolute Value Equations
Linear Equations
Piecewise Functions

Formulas

|x| = x if x ≥ 0, |x| = -x if x < 0
x_1 + 2x_2 = 8
x_1 - 2x_2 = 8
-x_1 + 2x_2 = 8
-x_1 - 2x_2 = 8

Theorems

Absolute Value Theorem
Linear Equation Solution Theorem

Suitable Grade Level

Grades 9-12