Let's break down the expression step by step:

\[
8 \times (10 - 6) \div 2 + 4
\]

1. First, solve the parentheses:
\[
10 - 6 = 4
\]
So, the expression becomes:
\[
8 \times 4 \div 2 + 4
\]

2. Now, perform the multiplication:
\[
8 \times 4 = 32
\]
The expression is now:
\[
32 \div 2 + 4
\]

3. Next, do the division:
\[
32 \div 2 = 16
\]
The expression becomes:
\[
16 + 4
\]

4. Finally, add:
\[
16 + 4 = 20
\]

So, the final result is:
\[
\boxed{20}
\]

Would you like further details or have any questions?

Here are 5 related questions to explore:
1. What happens if the order of operations is changed?
2. How would the result change if the division was before multiplication?
3. Can you rearrange the expression and still get the same result?
4. How does the answer change if one of the numbers inside the parentheses is negative?
5. How do parentheses affect the outcome in larger expressions?

**Tip:** Always follow the order of operations: parentheses, exponents, multiplication/division (left to right), and addition/subtraction (left to right).

Discover how to solve the arithmetic expression 8x (10-6) ÷ 2 + 4 using the order of operations. This problem focuses on key concepts like parentheses, multiplication, division, and addition, and is suitable for students in Grades 5-7.

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