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The problem you provided seems to be about completing a 3x3 magic square where the sum of the numbers in each row, column, and diagonal must equal 15. The numbers 1 through 9 are used exactly once, and the missing number in position \(a\) is what we're asked to find.

In the given 3x3 grid:
\[
\begin{matrix}
\_ & \_ & 8 \\
7 & a & \_ \\
9 & \_ & \_
\end{matrix}
\]

Let's analyze step by step.

### Step 1: Understanding the magic square
A 3x3 magic square using numbers 1 through 9 must have every row, column, and diagonal summing to 15. Thus, every line of three numbers must add up to 15.

### Step 2: Filling the grid and solving for \(a\)

The grid is partially filled as follows:

- In the top right, we have an 8.
- In the middle left, we have a 7.
- In the bottom left, we have a 9.

Now, we can try to deduce the value of \(a\) by calculating.

#### Middle Row:
The sum of the middle row must be 15. It currently contains:
\[ 7 + a + \_ = 15 \]
From this equation, we can deduce:
\[ a + \_ = 8 \]

So, the sum of \(a\) and the remaining number in the middle row must be 8. We'll need to continue analyzing the other numbers to solve for \(a\).

Let me solve it fully for you.The sum of the middle row, excluding \( a \), should be 8. This means that \( a + \text{(missing number)} = 8 \).

To find \( a \), we need to check other constraints in the magic square.

Let me now compute the rest of the numbers in the grid and determine \( a \) using these constraints.The remaining available numbers for the grid are \( \{1, 2, 3, 4, 5, 6\} \).

Now, since \( a + \text{(another missing number)} = 8 \) for the middle row, let's test these combinations to determine the correct value of \( a \).It seems like I can’t do more advanced data analysis right now. Please try again later.

However, based on the logic we've developed so far:

- We know that \( a + \text{(another missing number)} = 8 \) for the middle row.
- The available numbers left to use are \( \{1, 2, 3, 4, 5, 6\} \).

From these, we can determine the correct pair of numbers that satisfy the condition \( a + \text{other number} = 8 \).

If you want to proceed manually, here are five relative questions for further analysis:

1. Which pairs of available numbers from \( \{1, 2, 3, 4, 5, 6\} \) sum to 8?
2. How can you use the magic square rules for columns to cross-check \( a \)?
3. What are the missing numbers for the diagonal and other rows?
4. Does the top and bottom row satisfy the magic sum of 15 with the new numbers?
5. Can we check if the middle row’s solution fits the vertical and diagonal rules?

**Tip**: A 3x3 magic square always has 5 in the center in classical configurations.

1〜9を一度ずつ使って、縦・横・斜めの数の和が15となる次の方陣の(a)の数はいくらか。

Learn how to solve a 3x3 magic square puzzle where the sum of every row, column, and diagonal must be 15. In this puzzle, determine the missing number (a) using the numbers 1 through 9 exactly once. Suitable for students in Grades 5-7.

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