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The problem you have shared is related to completing a magic square, where the numbers 1 to 9 are used exactly once, and the sum of the numbers in each row, column, and diagonal must equal 15.

### Given partial 3x3 magic square:
```
8 ( ) 
7 (a) 
9
```
The problem is asking for the value of \(a\) in this grid.

### To solve:
1. In a 3x3 magic square, the sum of every row, column, and diagonal must be 15.
2. The middle cell (which is \(a\) here) is crucial, as it interacts with multiple rows, columns, and diagonals.
3. We already know that in a typical 3x3 magic square with numbers 1 to 9, the center value is always **5**. This value balances all the sums perfectly.

So, \( a = 5 \).

Would you like a detailed explanation of how a magic square is constructed or how we can verify the solution?

### Related questions:
1. How do we calculate the sum of rows, columns, and diagonals in a magic square?
2. Can the magic square be constructed in multiple ways with the same sum?
3. Why is the number in the center of a 3x3 magic square always 5?
4. How does the magic square relate to other number patterns?
5. What are the other properties of magic squares?

### Tip:
In any 3x3 magic square with numbers 1 to 9, the middle number will always be 5 to balance the sums of rows, columns, and diagonals.

1〜9を一度ずつ使って、縦・横・斜めの数の和が15となる次の方陣の(a)の数はいくらか。

Learn how to solve a 3x3 magic square by finding the missing value a. The goal is to make sure the sum of the numbers in each row, column, and diagonal equals 15. Suitable for students in Grades 5-7.

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