Math Problem Statement
Solution
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Problem 1:
Find all degree solutions for the following: Solution:
The cosine function equals zero at:
Here, represents the argument:
Divide by 5 to isolate :
Simplify:
Since cosine is periodic, all solutions are represented by:
Problem 2:
Find all solutions if :
Solution:
Recall that when . Therefore, we solve:
The cosine function equals at:
Simplify for by dividing by 3:
Find solutions in :
- Add :
- Add another :
Thus, the solutions are:
Final Answers:
- Problem 1:
- Problem 2:
Would you like further details or explanations?
Related Questions:
- What are the general forms for sine and cosine equations for periodicity?
- How does the secant function relate to the cosine function?
- Can you calculate similar solutions for sine equations?
- What happens to the range of solutions if the domain changes?
- How do transformations like or affect trigonometric functions?
Tip: Always simplify trigonometric identities to connect them with standard results like zeros of cosine and sine.
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Math Problem Analysis
Mathematical Concepts
Trigonometric Equations
Periodic Functions
Inverse Trigonometric Functions
Formulas
cos(θ) = 0 occurs at θ = 90° + 180°k, where k ∈ ℤ
sec(x) = -1 implies cos(x) = -1, and cos(x) = -1 at x = π + 2nπ, where n ∈ ℤ
Theorems
Periodic nature of cosine function
Relationship between secant and cosine
Suitable Grade Level
Grades 10-12
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