Math Problem Statement

Find all solutions of the equation csc^2(x) - cot(x) = 1 in the interval [0, 2π). Write your answer in radians in terms of π. If there is more than one solution, separate them with commas.

Solution

To solve the equation csc2xcotx=1\csc^2 x - \cot x = 1 in the interval [0,2π][0, 2\pi], we begin by rewriting the trigonometric identities in terms of sine and cosine:

cscx=1sinxandcotx=cosxsinx\csc x = \frac{1}{\sin x} \quad \text{and} \quad \cot x = \frac{\cos x}{\sin x}

Substituting these into the equation gives:

(1sinx)2cosxsinx=1\left(\frac{1}{\sin x}\right)^2 - \frac{\cos x}{\sin x} = 1

Multiply through by sin2x\sin^2 x to eliminate the denominators:

1cosxsinx=sin2x1 - \cos x \sin x = \sin^2 x

Now let's rearrange and use the Pythagorean identity sin2x+cos2x=1\sin^2 x + \cos^2 x = 1:

1cosxsinx=1cos2x1 - \cos x \sin x = 1 - \cos^2 x

Simplifying this, we find:

cosxsinx=cos2x\cos x \sin x = \cos^2 x

Rewriting cosxsinx\cos x \sin x as 12sin2x\frac{1}{2} \sin 2x:

12sin2x=cos2x\frac{1}{2} \sin 2x = \cos^2 x

Using the identity cos2x=1+cos2x2\cos^2 x = \frac{1 + \cos 2x}{2}:

12sin2x=1+cos2x2\frac{1}{2} \sin 2x = \frac{1 + \cos 2x}{2}

Equating and simplifying:

sin2x=1+cos2x\sin 2x = 1 + \cos 2x

Now, use sin2θ+cos2θ=1\sin^2 \theta + \cos^2 \theta = 1 for θ=2x\theta = 2x:

sin22x=(1+cos2x)2=1+2cos2x+cos22x\sin^2 2x = (1 + \cos 2x)^2 = 1 + 2\cos 2x + \cos^2 2x

From the Pythagorean identity:

1cos22x=1+2cos2x+cos22x1 - \cos^2 2x = 1 + 2\cos 2x + \cos^2 2x

This leads to:

2cos22x2cos2x=0-2\cos^2 2x - 2\cos 2x = 0

Factoring out 2-2:

cos2x(cos2x+1)=0\cos 2x (\cos 2x + 1) = 0

From here, the solutions are cos2x=0\cos 2x = 0 or cos2x=1\cos 2x = -1. Solving for xx gives:

2x=π2,3π2or2x=π2x = \frac{\pi}{2}, \frac{3\pi}{2} \quad \text{or} \quad 2x = \pi

Dividing by 2, the solutions for xx in [0,2π][0, 2\pi] are:

x=π4,3π4,π2x = \frac{\pi}{4}, \frac{3\pi}{4}, \frac{\pi}{2}

Thus, the solutions to the equation in the given interval are:

π4,3π4,π2\frac{\pi}{4}, \frac{3\pi}{4}, \frac{\pi}{2}

Would you like more details on any part of this solution or have any further questions?

Here are some related topics we could explore:

  1. More about trigonometric identities and their uses.
  2. What happens if we extend the domain beyond 00 to 2π2\pi.
  3. Techniques for solving trigonometric equations.
  4. How to graph equations involving trigonometric functions.
  5. The unit circle and its relationship to trigonometric functions.

Tip: When solving trigonometric equations, it's often helpful to consider using fundamental identities and transformations to simplify the equation into a more manageable form.

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Trigonometric Identities
Solving Trigonometric Equations

Formulas

csc(x) = 1 / sin(x)
cot(x) = cos(x) / sin(x)
Pythagorean identity: sin^2(x) + cos^2(x) = 1

Theorems

Pythagorean Identity

Suitable Grade Level

Grades 10-12