Math Problem Statement

Tell me the answer

Tell me the answer

Solution

To solve the problem step by step, we need to find the values of the digits (1st, 2nd, 3rd, and 4th digits) based on the given equations.

The equations are:

  1. 1stdigit+2nddigit=61^{st} \, \text{digit} + 2^{nd} \, \text{digit} = 6
  2. 4thdigit+3rddigit=154^{th} \, \text{digit} + 3^{rd} \, \text{digit} = 15
  3. 2nddigit+4thdigit=82^{nd} \, \text{digit} + 4^{th} \, \text{digit} = 8
  4. 1stdigit+4thdigit=141^{st} \, \text{digit} + 4^{th} \, \text{digit} = 14
  5. 3rddigit+1stdigit=133^{rd} \, \text{digit} + 1^{st} \, \text{digit} = 13

Let the digits be represented as x,y,z,wx, y, z, w where:

  • x=1stdigitx = 1^{st} \, \text{digit}
  • y=2nddigity = 2^{nd} \, \text{digit}
  • z=3rddigitz = 3^{rd} \, \text{digit}
  • w=4thdigitw = 4^{th} \, \text{digit}

Step-by-Step Solution

  1. From Equation 1:
    x+y=6(Equation A)x + y = 6 \quad \text{(Equation A)}

  2. From Equation 3:
    y+w=8(Equation B)y + w = 8 \quad \text{(Equation B)}

  3. From Equation 4:
    x+w=14(Equation C)x + w = 14 \quad \text{(Equation C)}

  4. From Equation 5:
    z+x=13(Equation D)z + x = 13 \quad \text{(Equation D)}

  5. From Equation 2:
    w+z=15(Equation E)w + z = 15 \quad \text{(Equation E)}


Solving for the digits:

  • From Equation C (x+w=14)(x + w = 14) and Equation A (x+y=6)(x + y = 6):
    Subtract x+y=6x + y = 6 from x+w=14x + w = 14:
    (x+w)(x+y)=146(x + w) - (x + y) = 14 - 6 wy=8(Equation F)w - y = 8 \quad \text{(Equation F)} So:
    w=y+8w = y + 8

  • Substitute w=y+8w = y + 8 into Equation B (y+w=8)(y + w = 8):
    y+(y+8)=8y + (y + 8) = 8 2y+8=82y + 8 = 8 2y=0y=02y = 0 \quad \Rightarrow \quad y = 0

  • Now that y=0y = 0, substitute yy into x+y=6x + y = 6 (Equation A):
    x+0=6x + 0 = 6 x=6x = 6

  • Substitute y=0y = 0 into w=y+8w = y + 8 (Equation F):
    w=0+8w = 0 + 8 w=8w = 8

  • Finally, substitute x=6x = 6 into z+x=13z + x = 13 (Equation D):
    z+6=13z + 6 = 13 z=7z = 7


Solution:

The digits are:

  • 1stdigit=61^{st} \, \text{digit} = 6
  • 2nddigit=02^{nd} \, \text{digit} = 0
  • 3rddigit=73^{rd} \, \text{digit} = 7
  • 4thdigit=84^{th} \, \text{digit} = 8

Verification:

  1. x+y=66+0=6x + y = 6 \quad \Rightarrow \quad 6 + 0 = 6
  2. w+z=158+7=15w + z = 15 \quad \Rightarrow \quad 8 + 7 = 15
  3. y+w=80+8=8y + w = 8 \quad \Rightarrow \quad 0 + 8 = 8
  4. x+w=146+8=14x + w = 14 \quad \Rightarrow \quad 6 + 8 = 14
  5. z+x=137+6=13z + x = 13 \quad \Rightarrow \quad 7 + 6 = 13

Thus, the solution is correct.


Final Answer:

The code is 6, 0, 7, 8.

Do you want me to explain any step in more detail?

Here are 5 related questions you might find interesting:

  1. How do you solve systems of equations with substitution?
  2. What is the elimination method for solving systems of equations?
  3. How can you represent real-world problems with systems of equations?
  4. How do you verify solutions to systems of linear equations?
  5. What are some applications of linear equations in daily life?

Tip: Always double-check your solution by substituting values back into the original equations!

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Math Problem Analysis

Mathematical Concepts

Algebra
Linear Equations
Systems of Equations

Formulas

x + y = 6
w + z = 15
y + w = 8
x + w = 14
z + x = 13

Theorems

Substitution Method
Elimination Method

Suitable Grade Level

Grades 6-8