Math Problem Statement

The image contains a mathematical puzzle involving equations with variables a, b, c, and d, arranged in a grid format. The sums of rows and columns are provided.

Solution

Problem Breakdown:

The given problem consists of two sets of equations involving sums of variables aa, bb, cc, and dd:

  1. The top set shows two squares, one with a+ba + b, and the other with c+bc + b. Together, these sums equal 15.
  2. The bottom set shows a similar layout with values (c+d =15 Let me break down and solve the problem in your image.

Step 1: Analyze the Problem

The grid involves four variables aa, bb, cc, and dd. The equations derived from the grid are:

  1. a+b=15a + b = 15
  2. c+d=15c + d = 15
  3. a+c=12a + c = 12
  4. b+d=2b + d = 2

We need to:

  1. Write the equations in terms of aa, bb, cc, and dd.
  2. Solve for the values of aa, bb, cc, and dd.

Step 2: Write the System of Equations

From the given sums:

  • a+b=15a + b = 15 \Rightarrow Equation 1
  • c+d=15c + d = 15 \Rightarrow Equation 2
  • a+c=12a + c = 12 \Rightarrow Equation 3
  • b+d=2b + d = 2 \Rightarrow Equation 4

Step 3: Solve the System of Equations

Using substitution:

  • From Equation 1: b=15ab = 15 - a
  • From Equation 2: d=15cd = 15 - c

Substitute bb and dd into Equation 4: (15a)+(15c)=2(15 - a) + (15 - c) = 2 Simplify: 30ac=2a+c=2830 - a - c = 2 \Rightarrow a + c = 28

Now we have two equations for a+ca + c:

  1. a+c=12a + c = 12 (from Equation 3)
  2. a+c=28a + c = 28 (contradiction suggests a misrepresentation).

Let us revisit and systematically solve the equations based on the relationships given in the image.

The system of equations extracted from the image is as follows:

  1. a+b=15a + b = 15 (Equation 1)
  2. c+d=15c + d = 15 (Equation 2)
  3. a+c=12a + c = 12 (Equation 3)
  4. b+d=2b + d = 2 (Equation 4)

Solve the Equations Step by Step:

  • From Equation 1: b=15ab = 15 - a
  • From Equation 2: d=15cd = 15 - c

Substitute b=15ab = 15 - a and d=15cd = 15 - c into Equation 4: (15a)+(15c)=2(15 - a) + (15 - c) = 2 Simplify: 30ac=230 - a - c = 2 a+c=28a + c = 28

Now we have two equations for a+ca + c:

  1. a+c=12a + c = 12 (Equation 3)
  2. a+c=28a + c = 28 (from solving Equation 4).

Clearly, the values of aa, bb, cc, and dd need reconciliation. Can you confirm the exact alignment of values in your query? If there’s a mismatch, I can resolve it further!

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Math Problem Analysis

Mathematical Concepts

Linear Equations
System of Equations

Formulas

a + b = 15
c + d = 15
a + c = 12
b + d = 2

Theorems

Basic Algebraic Techniques for Solving Systems of Equations

Suitable Grade Level

Grades 8-10