Math Problem Statement

4x+2y=16 x+2y=16

Solution

To solve the system of equations:

  1. 4x+2y=164x + 2y = 16
  2. x+2y=16x + 2y = 16

Step 1: Eliminate one variable

We can subtract the second equation from the first to eliminate yy:

(4x+2y)(x+2y)=1616(4x + 2y) - (x + 2y) = 16 - 16

3x=03x = 0

x=0x = 0

Step 2: Substitute x=0x = 0 into the second equation

Substituting x=0x = 0 into x+2y=16x + 2y = 16:

0+2y=160 + 2y = 16

2y=16y=82y = 16 \quad \Rightarrow \quad y = 8

Solution:

The solution to the system is: x=0,  y=8x = 0, \; y = 8

Verification:

  1. Substitute x=0,y=8x = 0, y = 8 into 4x+2y=164x + 2y = 16: 4(0)+2(8)=16True.4(0) + 2(8) = 16 \quad \text{True.}

  2. Substitute x=0,y=8x = 0, y = 8 into x+2y=16x + 2y = 16: 0+2(8)=16True.0 + 2(8) = 16 \quad \text{True.}

Final Answer:

(x,y)=(0,8)(x, y) = (0, 8)


Would you like a more detailed explanation or help with graphing?

Here are some related questions to explore:

  1. How do you graph this system of equations?
  2. What does elimination mean in solving systems of equations?
  3. Can this system have any other solutions?
  4. How do we solve systems using substitution instead of elimination?
  5. What is the geometrical interpretation of the solution?

Tip: Always verify your solution by substituting it back into the original equations!

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Math Problem Analysis

Mathematical Concepts

Algebra
Systems of Linear Equations
Elimination Method

Formulas

Subtracting one equation from another to eliminate a variable
Solving linear equations in the form ax + by = c

Theorems

Basic principles of solving linear systems by elimination

Suitable Grade Level

Grades 8-10