The problem is asking to solve a system of equations using substitution. The system provided is:

1. $y = 7x - 10$
2. $y = -3$

Steps to Solve:

1. Substitute $y = -3$ (from the second equation) into the first equation: $-3 = 7x - 10$

2. Solve for $x$: Add 10 to both sides: $-3 + 10 = 7x$ $7 = 7x$

   Divide both sides by 7: $x = 1$

3. Find $y$ (if necessary, though it’s already given as $y = -3$): Substituting $x = 1$ into $y = 7x - 10$: $y = 7(1) - 10$ $y = -3$

Final Answer:

The solution to the system is: $x = 1, \, y = -3$

Would you like me to explain the steps in more detail or assist with similar problems? Let me know!

Related Questions:

1. How do you solve systems of equations graphically?
2. What happens when two lines are parallel in a system of equations?
3. Can substitution be used for all systems of equations? Why or why not?
4. How do you solve a system using the elimination method?
5. What are examples of real-world problems involving systems of equations?

Tip:

Always check your solution by substituting both $x$ and $y$ into the original equations to verify correctness!