We will solve the system of equations using the substitution method. The given system of equations is:

1. $3x + 2y = 49$
2. $x = 3y - 2$

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Step 1: Substitute $x = 3y - 2$ into the first equation

Replace $x$ in $3x + 2y = 49$:

$3(3y - 2) + 2y = 49$

Simplify:

$9y - 6 + 2y = 49$

Combine like terms:

$11y - 6 = 49$

Add 6 to both sides:

$11y = 55$

Solve for $y$:

$y = 5$

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Step 2: Substitute $y = 5$ into $x = 3y - 2$

Use the second equation $x = 3y - 2$:

$x = 3(5) - 2$

Simplify:

$x = 15 - 2 = 13$

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Final Solution

The solution to the system is:

$\boxed{(13, 5)}$

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Correct Choice

A. The solution is $(13, 5)$.

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Would you like further details about the solution? Here are related questions to expand on this:

1. How can substitution be applied to systems of linear equations in general?
2. What are the conditions for a system of equations to have no solution or infinitely many solutions?
3. How can we verify the solution to a system of equations?
4. What other methods can be used to solve systems of linear equations?
5. Can substitution be used effectively for non-linear systems of equations?

Tip: Always verify the solution by substituting the values back into the original equations!