This is a system of linear equations:

$3x - y = 2$ $x + 2y = 3$

To solve it, let's use the substitution or elimination method. I'll proceed with the substitution method by solving for $x$ from the second equation and then substitute it into the first equation.

1. From the second equation: $x = 3 - 2y$

2. Substitute $x = 3 - 2y$ into the first equation: $3(3 - 2y) - y = 2$ Expanding: $9 - 6y - y = 2$ Combine like terms: $9 - 7y = 2$ $-7y = 2 - 9$ $-7y = -7$ $y = 1$

3. Substitute $y = 1$ back into the equation $x = 3 - 2y$: $x = 3 - 2(1)$ $x = 3 - 2$ $x = 1$

Thus, the solution to the system is: $(x, y) = (1, 1)$

Would you like a detailed step-by-step explanation, or do you have any questions about the process?

Here are 5 related questions to expand on this topic:

1. How can you verify that a solution to a system of equations is correct?
2. What are some alternative methods for solving a system of linear equations?
3. How does the elimination method work for systems of linear equations?
4. What happens if a system of equations has no solution or an infinite number of solutions?
5. How can systems of equations be solved graphically?

Tip: When solving a system of equations, it's often helpful to check your solution by substituting back into the original equations.