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This is a system of linear equations:

\[
3x - y = 2
\]
\[
x + 2y = 3
\]

To solve it, let's use the substitution or elimination method. I'll proceed with the substitution method by solving for \( x \) from the second equation and then substitute it into the first equation.

1. From the second equation:
   \[
   x = 3 - 2y
   \]

2. Substitute \( x = 3 - 2y \) into the first equation:
   \[
   3(3 - 2y) - y = 2
   \]
   Expanding:
   \[
   9 - 6y - y = 2
   \]
   Combine like terms:
   \[
   9 - 7y = 2
   \]
   \[
   -7y = 2 - 9
   \]
   \[
   -7y = -7
   \]
   \[
   y = 1
   \]

3. Substitute \( y = 1 \) back into the equation \( x = 3 - 2y \):
   \[
   x = 3 - 2(1)
   \]
   \[
   x = 3 - 2
   \]
   \[
   x = 1
   \]

Thus, the solution to the system is:
\[
(x, y) = (1, 1)
\]

Would you like a detailed step-by-step explanation, or do you have any questions about the process?

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Here are 5 related questions to expand on this topic:

1. How can you verify that a solution to a system of equations is correct?
2. What are some alternative methods for solving a system of linear equations?
3. How does the elimination method work for systems of linear equations?
4. What happens if a system of equations has no solution or an infinite number of solutions?
5. How can systems of equations be solved graphically?

**Tip:** When solving a system of equations, it's often helpful to check your solution by substituting back into the original equations.

Solve the system of equations: 3x - y = 2 and x + 2y = 3.

Learn how to solve the system of equations 3x - y = 2 and x + 2y = 3 using the substitution method. This problem covers key algebraic concepts, including linear equations and substitution, suitable for students in Grades 8-10.

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