Math Problem Statement

A certain grocery store sells oranges for $1.50 per pound and grapefruit for $1.20 per pound. You purchased a mix of oranges and grapefruits weighing 8 pounds total, which cost $10.35. If x is the number of pounds of grapefruit purchase, and y is the number of pounds of oranges purchased, the correct system of equations would be?

Solution

To solve this problem, you need to set up two equations based on the information provided:

  1. The total weight of oranges and grapefruits is 8 pounds. x+y=8x + y = 8 Here, xx represents the number of pounds of grapefruit, and yy represents the number of pounds of oranges.

  2. The total cost of the oranges and grapefruits is $10.35. The cost per pound for grapefruit is $1.20, and for oranges, it is $1.50. Therefore, the cost equation would be: 1.20x+1.50y=10.351.20x + 1.50y = 10.35

So, the system of equations is:

x + y = 8 \\ 1.20x + 1.50y = 10.35 \end{cases}$$ Would you like help solving this system of equations or more details on how to approach it? ### Expanding on the problem, here are 5 related questions: 1. What is the value of $$x$$ (the pounds of grapefruit) and $$y$$ (the pounds of oranges)? 2. If the cost per pound of oranges increased to $1.75, how would that change the system of equations? 3. What would the system of equations be if the total weight was 10 pounds instead of 8? 4. How much would 5 pounds of each fruit cost at the given prices? 5. What if you had purchased 10.35 pounds of fruit but still paid $10.35? ### Tip: To solve systems of equations, substitution and elimination methods are two powerful techniques that can simplify complex problems like this one!

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Math Problem Analysis

Mathematical Concepts

Linear Equations
Systems of Equations
Algebra

Formulas

x + y = 8 (total weight equation)
1.20x + 1.50y = 10.35 (total cost equation)

Theorems

Substitution Method
Elimination Method

Suitable Grade Level

Grades 8-10