Math Problem Statement

Solve the ODE(x1(t) x2(t))′=(2 −5 1 −2) (x1(t) x2(t))

Solution

To solve the given system of first-order linear ordinary differential equations, let’s write it out in vector form. The system is given by:

ddt(x1(t)x2(t))=(2512)(x1(t)x2(t)).\frac{d}{dt} \begin{pmatrix} x_1(t) \\ x_2(t) \end{pmatrix} = \begin{pmatrix} 2 & -5 \\ 1 & -2 \end{pmatrix} \begin{pmatrix} x_1(t) \\ x_2(t) \end{pmatrix}.

This is a system of linear differential equations, which can be solved by finding the eigenvalues and eigenvectors of the matrix A=(2512)A = \begin{pmatrix} 2 & -5 \\ 1 & -2 \end{pmatrix}.

Step 1: Find the Eigenvalues of AA

The eigenvalues λ\lambda of matrix AA are found by solving the characteristic equation:

det(AλI)=0.\det(A - \lambda I) = 0.

  1. Calculate AλIA - \lambda I:

    AλI=(2λ512λ).A - \lambda I = \begin{pmatrix} 2 - \lambda & -5 \\ 1 & -2 - \lambda \end{pmatrix}.

  2. Calculate the determinant:

    det(AλI)=(2λ)(2λ)(5)(1).\det(A - \lambda I) = (2 - \lambda)(-2 - \lambda) - (-5)(1).

    Expanding this, we get:

    λ22λ+5=0.\lambda^2 - 2\lambda + 5 = 0.

This characteristic polynomial has complex roots:

λ=1±i5.\lambda = -1 \pm i\sqrt{5}.

Step 2: Find the Eigenvectors

For each eigenvalue λ=1+i5\lambda = -1 + i\sqrt{5} and λ=1i5\lambda = -1 - i\sqrt{5}, we can find the corresponding eigenvector.

Step 3: General Solution

With complex eigenvalues, the solution will be of the form:

x(t)=eαt(C1cos(βt)v1+C2sin(βt)v2),\mathbf{x}(t) = e^{\alpha t} \left( C_1 \cos(\beta t) \mathbf{v}_1 + C_2 \sin(\beta t) \mathbf{v}_2 \right),

where α=1\alpha = -1, β=5\beta = \sqrt{5}, and v1\mathbf{v}_1 and v2\mathbf{v}_2 are the real and imaginary parts of the eigenvector associated with λ=1+i5\lambda = -1 + i\sqrt{5}.

Final Solution

The general solution is given by:

(x1(t)x2(t))=et(C1cos(5t)(112)+C2sin(5t)(112)).\begin{pmatrix} x_1(t) \\ x_2(t) \end{pmatrix} = e^{-t} \left( C_1 \cos(\sqrt{5} t) \begin{pmatrix} 1 \\ \frac{1}{2} \end{pmatrix} + C_2 \sin(\sqrt{5} t) \begin{pmatrix} 1 \\ \frac{1}{2} \end{pmatrix} \right).

Let me know if you need further details or explanations!

Related Questions

  1. How do we find eigenvalues and eigenvectors for a 2x2 matrix?
  2. What does it mean for an ODE to have complex eigenvalues, and how does it affect the solution?
  3. How do we interpret the terms eαtcos(βt)e^{\alpha t} \cos(\beta t) and eαtsin(βt)e^{\alpha t} \sin(\beta t) in the solution?
  4. How can we determine stability of solutions for such a system of ODEs?
  5. What is the physical interpretation of oscillatory solutions in dynamical systems?

Tip:

Always verify the stability of the system by examining the real part of the eigenvalues.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Ordinary Differential Equations (ODEs)
Linear Algebra
Eigenvalues and Eigenvectors
Complex Numbers

Formulas

dx/dt = A * x, where A is a matrix
Characteristic equation det(A - λI) = 0
General solution for complex eigenvalues: x(t) = e^(αt) * (C1 * cos(βt) * v1 + C2 * sin(βt) * v2)

Theorems

Eigenvalue theorem
Theory of systems of linear differential equations with constant coefficients

Suitable Grade Level

Undergraduate level