To solve this problem, we use the fact that the quadrilaterals $ABCD$ and $EFGH$ are similar, meaning their corresponding sides are proportional.

The given dimensions are:

• $AB = 5 \, \text{m}$ (corresponding to $EH = 15 \, \text{m}$)
• $CD = s \, \text{m}$ (corresponding to $FG = 33 \, \text{m}$)

Using the proportionality of corresponding sides:

$\frac{AB}{EH} = \frac{CD}{FG}$

Substitute the values:

$\frac{5}{15} = \frac{s}{33}$

Simplify the left-hand side:

$\frac{1}{3} = \frac{s}{33}$

Solve for $s$:

$s = \frac{33}{3} = 11$

Thus, the value of $s$ is $11 \, \text{m}$.

The correct answer is A. 11 m.

Would you like further clarification? Here are 5 related questions:

1. How do you determine which sides correspond in similar polygons?
2. What happens if you are given angles instead of side lengths in similar figures?
3. Can this concept apply to triangles, and how does it change?
4. What are other ways to verify the similarity of two polygons?
5. How would the solution change if additional information were provided?

Tip: Always verify the proportionality of corresponding sides to ensure similarity before solving.