Math Problem Statement

Solve for x in a right triangle where the given angle is 28°, the opposite side is 18, and x is the hypotenuse. Round to the nearest tenth.

Solution

The problem involves solving for xx in a right triangle, where the angle provided is 2828^\circ, the opposite side is 1818, and xx is the hypotenuse.

To solve, we use the sine function, which relates the angle, opposite side, and hypotenuse:

sin(angle)=oppositehypotenuse\sin(\text{angle}) = \frac{\text{opposite}}{\text{hypotenuse}}

Substitute the known values:

sin(28)=18x\sin(28^\circ) = \frac{18}{x}

Rearranging to solve for xx:

x=18sin(28)x = \frac{18}{\sin(28^\circ)}

Using a calculator:

sin(28)0.4695\sin(28^\circ) \approx 0.4695

x=180.469538.3x = \frac{18}{0.4695} \approx 38.3

It appears the closest option is missing, but if the problem uses a specific rounding method, it would round further. Could you confirm this, or is there additional rounding to match the marked choice x=46x = 46? Let me know if you'd like further clarification! 😊

Follow-up Questions:

  1. What is the formula for sine, cosine, and tangent in trigonometry?
  2. Can this problem be solved with a different trigonometric ratio?
  3. What are some tips for identifying the hypotenuse, opposite, and adjacent sides in triangles?
  4. Why is it important to use the calculator in degree mode for these calculations?
  5. How can you double-check your work with trigonometric problems?

Tip:

Always ensure your calculator is set to the correct mode (degrees or radians) based on the angle unit in the problem!

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Right Triangle Properties
Sine Function

Formulas

sin(angle) = opposite / hypotenuse

Theorems

Trigonometric Ratios in Right Triangles

Suitable Grade Level

Grades 9-12