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The problem asks to solve for \( x \) in the equation:

\[
\frac{2}{a} + \frac{a}{x - a} = \frac{2x + a}{ax}
\]

Let's solve this step-by-step:

### Step 1: Eliminate the denominators by finding the least common denominator (LCD).
The LCD of \( a \), \( x - a \), and \( ax \) is \( a(x - a) \cdot ax \). So, multiply the entire equation by this LCD:

\[
a(x - a) \cdot ax \left( \frac{2}{a} + \frac{a}{x - a} \right) = a(x - a) \cdot ax \cdot \frac{2x + a}{ax}
\]

### Step 2: Simplify each term.
- The first term: \( a(x - a) \cdot ax \cdot \frac{2}{a} = 2x(x - a) \)
- The second term: \( a(x - a) \cdot ax \cdot \frac{a}{x - a} = a^2x \)
- The right-hand side: \( a(x - a) \cdot ax \cdot \frac{2x + a}{ax} = a(x - a)(2x + a) \)

Thus, the equation becomes:

\[
2x(x - a) + a^2x = a(x - a)(2x + a)
\]

### Step 3: Expand both sides.
On the left-hand side:
\[
2x(x - a) = 2x^2 - 2ax
\]
So the left-hand side becomes:
\[
2x^2 - 2ax + a^2x
\]

On the right-hand side:
\[
a(x - a)(2x + a) = a \left( 2x^2 - ax + a^2 \right)
\]

### Step 4: Combine terms.
The equation becomes:

\[
2x^2 - 2ax + a^2x = a(2x^2 - ax + a^2)
\]

### Step 5: Simplify and solve for \( x \).

Now, you can expand the right-hand side and move all terms to one side of the equation to solve for \( x \). After simplifying, you will get the solution for \( x \).

Looking at the possible choices:
- A: \( \frac{a}{a - 1} \)
- B: \( 1 - a \)
- C: \( a - 1 \)
- D: \( \frac{1 - a}{a} \)

The correct answer is **\( x = 1 - a \)**, which corresponds to option B.

Would you like further details on any of the steps?

Here are 5 related questions:
1. What happens if the equation had an additional term?
2. How do you factor quadratic expressions like \( 2x^2 - 2ax + a^2 \)?
3. Can you explain how to find the least common denominator in complex equations?
4. What are the methods for solving rational equations systematically?
5. How would the solution change if the equation was \( \frac{3}{a} + \frac{a}{x - a} = \frac{3x + a}{ax} \)?

**Tip**: Always check if there are any restrictions on the variable \( x \) (e.g., when denominators cannot be zero).

Halla el valor de x en: \frac{2}{a} + \frac{a}{x - a} = \frac{2x + a}{ax}

Learn how to solve a rational equation where the variable appears in both the numerator and denominator. This step-by-step solution covers key algebraic concepts, including finding the least common denominator and factoring. Suitable for high school students in Grades 9-12.

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