Math Problem Statement

x=5

p(x) = (x + 7)^2 - 15, x = 5

Solution

The given equation from the image is:

p(x)=(x+7)215p(x) = (x + 7)^2 - 15

You mentioned that x=5x = 5, so we will substitute x=5x = 5 into the equation and solve for p(5)p(5).

Let's calculate it step by step:

p(5)=(5+7)215p(5) = (5 + 7)^2 - 15

Now, simplifying inside the parentheses:

p(5)=(12)215p(5) = (12)^2 - 15

Next, square the 12:

p(5)=14415p(5) = 144 - 15

Finally, subtract 15 from 144:

p(5)=129p(5) = 129

So, the value of p(5)p(5) is 129.

Would you like further details or have any questions?

Here are some related questions to expand on this concept:

  1. What happens to the function if x=7x = -7?
  2. How can you find the vertex of the quadratic function p(x)=(x+7)215p(x) = (x + 7)^2 - 15?
  3. What are the roots (solutions) of the equation p(x)=0p(x) = 0?
  4. How does the graph of this quadratic function look like?
  5. What is the general form of a quadratic function, and how does it relate to this one?

Tip: For quadratic functions in the form (x+a)2+b(x + a)^2 + b, the vertex of the parabola is at the point (a,b)(-a, b).

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Math Problem Analysis

Mathematical Concepts

Algebra
Quadratic Functions
Function Evaluation

Formulas

p(x) = (x + a)^2 + b
p(5) = (5 + 7)^2 - 15

Theorems

Basic properties of quadratic functions

Suitable Grade Level

Grades 8-10