To find the value of \( Y \) when \( x = -7 \), we substitute \( -7 \) for \( x \) in the equation:

\[
Y = x^2 - 10x + 15
\]

Substitute \( x = -7 \):

\[
Y = (-7)^2 - 10(-7) + 15
\]

Now, calculate step by step:

1. \( (-7)^2 = 49 \)
2. \( -10(-7) = 70 \)
3. Add the results: 

\[
Y = 49 + 70 + 15 = 134
\]

So, when \( x = -7 \), \( Y = 134 \).

Would you like further details on any step?

Here are 5 related questions to expand on this:

1. What is the value of \( Y \) when \( x = 3 \)?
2. How can you find the vertex of the quadratic equation \( Y = x^2 - 10x + 15 \)?
3. What does the graph of \( Y = x^2 - 10x + 15 \) look like?
4. How can you complete the square for \( Y = x^2 - 10x + 15 \)?
5. What are the roots of the equation \( Y = x^2 - 10x + 15 = 0 \)?

**Tip:** To solve quadratic equations like this one, the quadratic formula can be very useful if factoring is difficult.

Y = x² - 10x + 15. If x is equal to -7, what is the value of Y?

Learn how to solve the quadratic equation Y = x² - 10x + 15 by substituting x = -7. This problem demonstrates the application of algebraic substitution to evaluate quadratic functions, suitable for students in Grades 8-10.

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