Math Problem Statement

Solve

Solution

The image contains three math problems. I'll solve each one and provide the answers with explanations.

Problem 1:

2(2x+3)=4x+82(2x + 3) = 4x + 8 We are asked to find the value of xx that satisfies this equation.

Solution:

  1. Distribute the 22 on the left side: 4x+6=4x+84x + 6 = 4x + 8
  2. Subtract 4x4x from both sides: 6=86 = 8 This is a contradiction, which means the equation has no solution.

Problem 2:

This problem involves analyzing a graph and solving based on its features. The graph represents a parabola.

Problem Statement: Determine the range of xx where the height yy of the projectile is at least 8 meters.

Solution:

  • The graph shows a parabola with its vertex at x=3x = 3 and y=10y = 10 meters.
  • The height of 8 meters corresponds to points where the parabola crosses y=8y = 8.

By analyzing the graph:

  • The parabola crosses y=8y = 8 at approximately x=2x = 2 and x=4x = 4.
  • Thus, the range of xx where the height is at least 8 meters is 2x42 \leq x \leq 4.

Problem 3:

Problem Statement: Two poles, A and B, are located 60 meters apart. The height of pole A is 20 meters, and the height of pole B is 40 meters. A rope is tied from the top of pole A to the top of pole B. What is the height of the rope when it is at a point directly above the point on the ground that is 30 meters from both poles?

Solution: This is a classic application of similar triangles.

Let's denote the height of the rope above the ground at the midpoint between the two poles as hh. The midpoint is 30 meters from each pole.

  1. Since the point is equidistant from both poles: Using the similarity of triangles: h30=402060\text{Using the similarity of triangles: } \frac{h}{30} = \frac{40 - 20}{60}
  2. Simplifying: h30=2060=13\frac{h}{30} = \frac{20}{60} = \frac{1}{3} So, h=10h = 10 meters.

Thus, the height of the rope at that point is 10 meters.


If you need further details on any of these solutions or have any questions, feel free to ask!

Relative Questions:

  1. How do you determine when a quadratic equation has no solution?
  2. What are the properties of a parabola that help in solving graph-based questions?
  3. How do you apply the concept of similar triangles in real-life problems?
  4. What is the significance of the vertex in a parabolic graph?
  5. How do you solve linear equations with variables on both sides?
  6. What is the range and how is it determined in the context of a graph?
  7. How can contradictions in algebraic equations be identified?
  8. How can you find the point where a rope is at its lowest height between two poles?

Tip:

Always check for contradictions when solving equations; if both sides simplify to a false statement, the equation has no solution.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Algebra
Quadratic Equations
Graph Analysis
Similar Triangles

Formulas

Quadratic equation solving
Vertex form of a parabola

Theorems

Properties of parabolas
Similarity in triangles

Suitable Grade Level

Grades 9-12