Math Problem Statement

Solve the quadratic equations: x^2 - 9x + 20 = 0 (factorization), 2x^2 + 12x + 10 = 0 (completing the square), 6x^2 - 11x - 7 = 0 (quadratic formula), and x^2 + 3x - 18 = 0 (quadratic formula).

Solution

Let's solve these problems step by step:

1. Solve x29x+20=0x^2 - 9x + 20 = 0 using factorization.

The equation is x29x+20=0x^2 - 9x + 20 = 0.

  • Find two numbers whose product is 20 (constant term) and sum is -9 (coefficient of xx).
    • The numbers are -5 and -4.
  • Rewrite the middle term: x25x4x+20=0x^2 - 5x - 4x + 20 = 0
  • Group terms and factorize: x(x5)4(x5)=0x(x - 5) - 4(x - 5) = 0 (x5)(x4)=0(x - 5)(x - 4) = 0
  • Solve for xx: x5=0orx4=0x - 5 = 0 \quad \text{or} \quad x - 4 = 0 x=5orx=4x = 5 \quad \text{or} \quad x = 4

Solution: x=5,x=4x = 5, x = 4


2. Solve 2x2+12x+10=02x^2 + 12x + 10 = 0 using the complete square method.

The equation is 2x2+12x+10=02x^2 + 12x + 10 = 0.

  1. Divide through by 2 to simplify: x2+6x+5=0x^2 + 6x + 5 = 0
  2. Rewrite x2+6x+5=0x^2 + 6x + 5 = 0 by completing the square:
    • Take half of 6 (coefficient of xx) and square it: (6/2)2=9(6/2)^2 = 9.
    • Add and subtract 9: x2+6x+99+5=0x^2 + 6x + 9 - 9 + 5 = 0
    • Simplify: (x+3)24=0(x + 3)^2 - 4 = 0
  3. Solve for xx: (x+3)2=4(x + 3)^2 = 4 x+3=±2x + 3 = \pm 2 x=3+2=1orx=32=5x = -3 + 2 = -1 \quad \text{or} \quad x = -3 - 2 = -5

Solution: x=1,x=5x = -1, x = -5


3a. Solve 6x211x7=06x^2 - 11x - 7 = 0 using the quadratic formula.

The quadratic formula is: x=b±b24ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} Here, a=6a = 6, b=11b = -11, c=7c = -7.

  1. Calculate the discriminant: Δ=b24ac=(11)24(6)(7)=121+168=289\Delta = b^2 - 4ac = (-11)^2 - 4(6)(-7) = 121 + 168 = 289
  2. Solve for xx: x=(11)±2892(6)=11±1712x = \frac{-(-11) \pm \sqrt{289}}{2(6)} = \frac{11 \pm 17}{12} x=11+1712=2812=73x = \frac{11 + 17}{12} = \frac{28}{12} = \frac{7}{3} x=111712=612=12x = \frac{11 - 17}{12} = \frac{-6}{12} = -\frac{1}{2}

Solution: x=73,x=12x = \frac{7}{3}, x = -\frac{1}{2}


3b. Solve x2+3x18=0x^2 + 3x - 18 = 0 using the quadratic formula.

The equation is x2+3x18=0x^2 + 3x - 18 = 0.

  1. Calculate the discriminant: Δ=b24ac=(3)24(1)(18)=9+72=81\Delta = b^2 - 4ac = (3)^2 - 4(1)(-18) = 9 + 72 = 81
  2. Solve for xx: x=3±812(1)=3±92x = \frac{-3 \pm \sqrt{81}}{2(1)} = \frac{-3 \pm 9}{2} x=3+92=62=3x = \frac{-3 + 9}{2} = \frac{6}{2} = 3 x=392=122=6x = \frac{-3 - 9}{2} = \frac{-12}{2} = -6

Solution: x=3,x=6x = 3, x = -6


Do you need further clarification on any step or method? Here are 5 questions to deepen understanding:

  1. What are other methods for solving quadratic equations besides factorization, completing the square, and quadratic formula?
  2. How can you verify the roots of a quadratic equation?
  3. Can every quadratic equation be solved by factorization? Why or why not?
  4. How does the discriminant (Δ\Delta) affect the nature of roots?
  5. Why is completing the square a useful method for deriving the quadratic formula?

Tip: Always check your solutions by substituting the values of xx back into the original equation!

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Math Problem Analysis

Mathematical Concepts

Algebra
Quadratic Equations
Factorization
Completing the Square
Quadratic Formula

Formulas

Quadratic equation formula: x = (-b ± √(b^2 - 4ac)) / 2a
Factorization method for quadratic equations
Completing the square method: ax^2 + bx + c = 0 transformed to (x + p)^2 = q

Theorems

Quadratic formula theorem
Properties of perfect square trinomials

Suitable Grade Level

Grades 8-10