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To find the height from which the object was kicked, we need to determine the initial height of the object. The equation provided is:

\[ h = -4.9t^2 + 7t + 9 \]

In this equation, \( h \) represents the height above the ground in meters, and \( t \) represents the time in seconds after the object is kicked. The initial height of the object corresponds to the height when \( t = 0 \).

Let's substitute \( t = 0 \) into the equation to find the initial height \( h \):

\[
h = -4.9(0)^2 + 7(0) + 9
\]

\[
h = 9
\]

Thus, the initial height of the object from which it was kicked is 9 meters. The correct answer is **D) 9**.

Would you like more details on this solution or have any further questions?

Here are some related questions:
1. How does the quadratic equation describe the motion of a projectile?
2. What does the coefficient of \( t^2 \) in the equation represent?
3. How can you determine the time at which the object reaches its maximum height?
4. What would be the impact of changing the initial velocity on the maximum height?
5. How can you calculate the time the object hits the ground?
6. What is the significance of the constant term in the equation?
7. How would air resistance affect the object's motion?
8. How can you derive the equation for the object's velocity at any time?

**Tip:** Remember that the constant term in the quadratic equation for projectile motion gives the initial height from which the object is launched.

Learn how to solve the quadratic equation -4.9t^2 + 7t + 9 to find the initial height from which an object was kicked. This problem involves projectile motion and the quadratic equation formula. Suitable for students in Grades 10-12.

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