The given expression is:

\[
\frac{1}{k} : \frac{3}{1} = \frac{2}{4} : \frac{p}{1}
\]

This can be rewritten as a proportion:

\[
\frac{\frac{1}{k}}{\frac{3}{1}} = \frac{\frac{2}{4}}{\frac{p}{1}}
\]

Now, simplify both sides:

\[
\frac{\frac{1}{k}}{\frac{3}{1}} = \frac{1}{3k}
\quad \text{and} \quad
\frac{\frac{2}{4}}{\frac{p}{1}} = \frac{1}{2p}
\]

This gives the equation:

\[
\frac{1}{3k} = \frac{1}{2p}
\]

Cross-multiply:

\[
2p = 3k
\]

Now, we can find a relation between \( p \) and \( k \):

\[
p = \frac{3k}{2}
\]

Therefore, \( p \) depends on \( k \). To fully determine \( k \) and \( p \), we need additional information or constraints.

Do you have more information about the values of \( k \) or \( p \)?

If you'd like more details or have any questions, let me know! Here are some related questions:

1. What methods can we use to solve ratios and proportions?
2. How do cross-multiplication rules work in solving proportions?
3. What is the importance of simplifying ratios?
4. How can unknowns in ratios be solved with given constraints?
5. What are some common applications of proportions in real life?

**Tip:** Always simplify ratios first to make calculations easier!

Learn how to solve the proportion problem 1:k:3 = 2:4:p. This solution involves ratios, proportions, and cross-multiplication, making it suitable for students in Grades 6-8. Follow the step-by-step explanation and master solving equations with unknowns.

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