Math Problem Statement

An object moving along a coordinate line has acceleration a = d^2s/dt^2 = (64/pi^2) * cos(8t/pi); its initial velocity and initial position are given by v(0) = 4 and s(0) = 5. Find the object's position at time t.

Solution

This problem is asking to find the position function s(t)s(t) of an object moving along a line, given the following information:

  1. The acceleration is a(t)=d2sdt2=64π2cos(8tπ)a(t) = \frac{d^2 s}{dt^2} = \frac{64}{\pi^2} \cos\left(\frac{8t}{\pi}\right).
  2. The initial velocity is v(0)=4v(0) = 4 and the initial position is s(0)=5s(0) = 5.

To solve for the position function s(t)s(t), we need to follow these steps:

Step 1: Find the velocity function v(t)v(t)

We integrate the acceleration a(t)a(t) to find the velocity function.

v(t)=a(t)dt=64π2cos(8tπ)dtv(t) = \int a(t) \, dt = \int \frac{64}{\pi^2} \cos\left(\frac{8t}{\pi}\right) \, dt

We can use the fact that the integral of cos(kx)\cos(kx) is 1ksin(kx)\frac{1}{k} \sin(kx), where kk is the coefficient of xx. In this case, k=8πk = \frac{8}{\pi}.

So,

v(t)=64π2π8sin(8tπ)+C1v(t) = \frac{64}{\pi^2} \cdot \frac{\pi}{8} \sin\left(\frac{8t}{\pi}\right) + C_1 v(t)=8πsin(8tπ)+C1v(t) = \frac{8}{\pi} \sin\left(\frac{8t}{\pi}\right) + C_1

Step 2: Use initial condition v(0)=4v(0) = 4

To find the constant C1C_1, use the initial condition v(0)=4v(0) = 4.

At t=0t = 0: v(0)=8πsin(8(0)π)+C1=4v(0) = \frac{8}{\pi} \sin\left(\frac{8(0)}{\pi}\right) + C_1 = 4 sin(0)=0,soC1=4\sin(0) = 0, \quad \text{so} \quad C_1 = 4

Thus, the velocity function becomes: v(t)=8πsin(8tπ)+4v(t) = \frac{8}{\pi} \sin\left(\frac{8t}{\pi}\right) + 4

Step 3: Find the position function s(t)s(t)

Now, integrate v(t)v(t) to find the position function s(t)s(t):

s(t)=v(t)dt=(8πsin(8tπ)+4)dts(t) = \int v(t) \, dt = \int \left( \frac{8}{\pi} \sin\left(\frac{8t}{\pi}\right) + 4 \right) dt

The integral of sin(kx)\sin(kx) is 1kcos(kx)-\frac{1}{k} \cos(kx), so:

s(t)=8ππ8cos(8tπ)+4t+C2s(t) = -\frac{8}{\pi} \cdot \frac{\pi}{8} \cos\left(\frac{8t}{\pi}\right) + 4t + C_2 s(t)=cos(8tπ)+4t+C2s(t) = -\cos\left(\frac{8t}{\pi}\right) + 4t + C_2

Step 4: Use initial condition s(0)=5s(0) = 5

To find the constant C2C_2, use the initial condition s(0)=5s(0) = 5.

At t=0t = 0: s(0)=cos(0)+4(0)+C2=5s(0) = -\cos(0) + 4(0) + C_2 = 5 cos(0)=1,so1+C2=5-\cos(0) = -1, \quad \text{so} \quad -1 + C_2 = 5 C2=6C_2 = 6

Thus, the position function is: s(t)=cos(8tπ)+4t+6s(t) = -\cos\left(\frac{8t}{\pi}\right) + 4t + 6

Final Answer:

s(t)=cos(8tπ)+4t+6s(t) = -\cos\left(\frac{8t}{\pi}\right) + 4t + 6

Would you like more details on this solution or have any questions?

Here are some related questions to extend your understanding:

  1. How would you find the velocity at any given time tt?
  2. What is the object's acceleration at t=0t = 0?
  3. How would the problem change if the initial velocity was zero?
  4. Can you describe the motion of the object based on the cosine term in the position function?
  5. How does the amplitude of the cosine function affect the object's motion?

Tip: Always check your integration constants by using the given initial conditions to ensure accuracy.

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Math Problem Analysis

Mathematical Concepts

Differential Equations
Kinematics

Formulas

Integration of acceleration to find velocity
Integration of velocity to find position

Theorems

Fundamental Theorem of Calculus
Initial Value Problem

Suitable Grade Level

Grades 11-12, Early College