To find the average velocity of the object on the interval $[2, 5]$, we will use the formula for average velocity:

$\text{Average velocity} = \frac{s(b) - s(a)}{b - a}$

where $s(t)$ is the position function, and $[a, b]$ is the time interval. In this case, $s(t) = t^2 - 4t + 3$, and the interval is $[2, 5]$.

Step 1: Find $s(5)$

$s(5) = 5^2 - 4(5) + 3 = 25 - 20 + 3 = 8$

Step 2: Find $s(2)$

$s(2) = 2^2 - 4(2) + 3 = 4 - 8 + 3 = -1$

Step 3: Calculate the average velocity

$\text{Average velocity} = \frac{s(5) - s(2)}{5 - 2} = \frac{8 - (-1)}{5 - 2} = \frac{8 + 1}{3} = \frac{9}{3} = 3 \, \text{feet per second}$

Final Answer:

The average velocity of the object on the interval $[2, 5]$ is $3 \, \text{feet per second}$.

Would you like more details on any of these steps or have any other questions?

Here are 5 related questions:

1. How do you find the instantaneous velocity from the position function?
2. What is the difference between average velocity and instantaneous velocity?
3. How would the average velocity change if the interval was $[1, 5]$ instead of $[2, 5]$?
4. What is the significance of the sign (positive or negative) of velocity?
5. How can you interpret the position function graphically to understand velocity?

Tip: The average velocity is the slope of the secant line connecting two points on the position function graph over a given interval.