Math Problem Statement
Work out the missing side x in each triangle using trigonometric ratios. Give your answers to 1 decimal place or better.
Solution
To solve these right-angled triangles, we can use trigonometric ratios (sine, cosine, and tangent) based on the angles provided. Let's go through each triangle.
-
Top Left Triangle:
- Given: Opposite side = , Hypotenuse = 5 cm, Angle = 29°
- Using sine:
- Solving for :
- cm
-
Top Middle Triangle:
- Given: Adjacent side = 7 cm, Hypotenuse = , Angle = 17°
- Using cosine:
- Solving for :
- cm
-
Top Right Triangle:
- Given: Adjacent side = 4 cm, Opposite side = , Angle = 65°
- Using tangent:
- Solving for :
- cm
-
Bottom Left Triangle:
- Given: Opposite side = , Hypotenuse = 4.1 cm, Angle = 25°
- Using sine:
- Solving for :
- cm
-
Bottom Middle Triangle:
- Given: Opposite side = , Adjacent side = 4.4 cm, Angle = 41°
- Using tangent:
- Solving for :
- cm
-
Bottom Right Triangle:
- Given: Adjacent side = 3.1 cm, Opposite side = , Angle = 53°
- Using tangent:
- Solving for :
- cm
Answers (to 1 decimal place):
- cm
- cm
- cm
- cm
- cm
- cm
Would you like more detailed steps for each calculation, or have any questions?
Related Questions:
- How do trigonometric functions relate to side lengths in right triangles?
- What is the difference between using sine, cosine, and tangent in right triangles?
- How would these calculations change if we knew two side lengths but not the angle?
- How can we verify these results using the Pythagorean theorem?
- Can these methods apply to non-right triangles?
Tip:
Always double-check the angle and side placement relative to each other to choose the correct trigonometric ratio!
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Math Problem Analysis
Mathematical Concepts
Trigonometry
Right-angled triangles
Formulas
sin(angle) = opposite / hypotenuse
cos(angle) = adjacent / hypotenuse
tan(angle) = opposite / adjacent
Theorems
Trigonometric ratios in right-angled triangles
Suitable Grade Level
Grades 9-10