Math Problem Statement

z = 4x + log x + log y

Solution

The given equation is:

z=4x+logx+logyz = 4x + \log x + \log y

Here, zz is expressed in terms of xx and yy, where logx\log x and logy\log y refer to logarithms (usually assumed to be base 10 unless specified otherwise).

Rearranging or Manipulating the Equation:

  1. To isolate yy, we can subtract 4x+logx4x + \log x from both sides: z4xlogx=logyz - 4x - \log x = \log y
  2. Exponentiating both sides to eliminate the logarithm: y=10z4xlogxy = 10^{z - 4x - \log x}

Thus, yy can be expressed as: y=10z4xlogxy = 10^{z - 4x - \log x}

Would you like more details or have any specific questions?

Related Questions:

  1. How would the equation change if natural logarithms (ln) were used instead of base 10 logarithms?
  2. Can you find the partial derivative of zz with respect to xx?
  3. What happens to the equation when zz is held constant and we differentiate with respect to xx?
  4. How does the value of yy change when zz is increased by a constant?
  5. How can this equation be graphed in a 3D plot with respect to xx, yy, and zz?

Tip:

When dealing with logarithmic equations, always ensure that the argument of the logarithm (here xx and yy) is positive, as logarithms are undefined for non-positive values.

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Math Problem Analysis

Mathematical Concepts

Algebra
Logarithms
Exponentiation

Formulas

z = 4x + log x + log y
y = 10^{z - 4x - log x}

Theorems

Properties of Logarithms
Exponentiation

Suitable Grade Level

Grades 10-12