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To solve the inequality \( 3b + 4 < 1 \) for \( b \), follow these steps:

1. **Subtract 4 from both sides of the inequality:**

   \[
   3b + 4 - 4 < 1 - 4
   \]

   Simplifying this gives:

   \[
   3b < -3
   \]

2. **Divide both sides by 3 to isolate \( b \):**

   \[
   \frac{3b}{3} < \frac{-3}{3}
   \]

   Simplifying this gives:

   \[
   b < -1
   \]

So, the solution to the inequality \( 3b + 4 < 1 \) is \( b < -1 \).

Would you like any more details or have any questions on this solution?

Here are five related questions to expand your understanding:
1. How would you solve the inequality \( 5b - 7 > 3 \)?
2. What is the solution to the inequality \( 4b + 2 \leq 10 \)?
3. Can you solve \( 2b - 8 \geq 4 \)?
4. How would you approach solving \( -3b + 5 < 2 \)?
5. What steps would you take to solve \( 6b + 1 \geq 0 \)?

**Tip:** When solving inequalities, remember that if you multiply or divide both sides of an inequality by a negative number, you must reverse the inequality sign.

Learn how to solve the linear inequality 3b + 4 < 1 with a detailed step-by-step explanation. This problem covers key algebraic concepts, such as solving inequalities and linear equations. Suitable for students in Grades 7-9.

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