To solve the inequality $3b + 4 < 1$ for $b$, follow these steps:

1. Subtract 4 from both sides of the inequality:

   $3b + 4 - 4 < 1 - 4$

   Simplifying this gives:

   $3b < -3$

2. Divide both sides by 3 to isolate $b$:

   $\frac{3b}{3} < \frac{-3}{3}$

   Simplifying this gives:

   $b < -1$

So, the solution to the inequality $3b + 4 < 1$ is $b < -1$.

Would you like any more details or have any questions on this solution?

Here are five related questions to expand your understanding:

1. How would you solve the inequality $5b - 7 > 3$?
2. What is the solution to the inequality $4b + 2 \leq 10$?
3. Can you solve $2b - 8 \geq 4$?
4. How would you approach solving $-3b + 5 < 2$?
5. What steps would you take to solve $6b + 1 \geq 0$?

Tip: When solving inequalities, remember that if you multiply or divide both sides of an inequality by a negative number, you must reverse the inequality sign.