Solve  $18\le3(b-4)$18≤3(b−4)​ .

To solve the inequality $ 18 \leq 3(b - 4) $, follow these steps:

### Step 1: Divide both sides by 3
Since we want to isolate $ b $, start by dividing both sides of the inequality by 3 to simplify:

\[
\frac{18}{3} \leq \frac{3(b - 4)}{3}
\]

\[
6 \leq b - 4
\]

### Step 2: Add 4 to both sides
To isolate $ b $, add 4 to both sides of the inequality:

\[
6 + 4 \leq b
\]

\[
10 \leq b
\]

### Final Answer:
The solution is:

\[
b \geq 10
\]

This means $ b $ must be greater than or equal to 10.

Would you like any further details or have questions?

Here are 5 related questions:
1. How do you solve an inequality with a negative coefficient?
2. What happens when you multiply or divide an inequality by a negative number?
3. How would the solution change if the inequality were $ 18 > 3(b - 4) $?
4. Can you solve compound inequalities like $ 5 < 2b + 3 \leq 11 $?
5. How do you graph the solution to an inequality on a number line?

**Tip**: Always remember that multiplying or dividing both sides of an inequality by a negative number reverses the inequality sign.

Learn how to solve the inequality 18 ≤ 3(b - 4) with a detailed, step-by-step solution. This problem involves key algebraic concepts like solving inequalities and applying the distributive property. Suitable for students in Grades 6-8.

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