The given function is $f(x) = 6 - 8x$, and the problem asks to find the values of the function at specific inputs:

(a) $f(-8)$

We substitute $x = -8$ into the function:

$f(-8) = 6 - 8(-8) = 6 + 64 = 70$

(b) $f(0)$

We substitute $x = 0$ into the function:

$f(0) = 6 - 8(0) = 6$

(c) $f(8)$

We substitute $x = 8$ into the function:

$f(8) = 6 - 8(8) = 6 - 64 = -58$

Therefore, the values are:

• (a) $f(-8) = 70$
• (b) $f(0) = 6$
• (c) $f(8) = -58$

Would you like further explanation or additional details? Here are five related questions to expand on this:

1. How do you graph linear functions like $f(x) = 6 - 8x$?
2. What does the slope of $-8$ in $f(x) = 6 - 8x$ represent?
3. How do we find the x-intercept and y-intercept of $f(x) = 6 - 8x$?
4. What happens to the function $f(x)$ as $x \to \infty$ or $x \to -\infty$?
5. How would the graph of $f(x) = 6 - 8x$ compare to $g(x) = 6 + 8x$?

Tip: When working with linear functions, the slope $m$ determines how steep the line is and in which direction it slants.