Math Problem Statement

Evaluate the functions.

  1. f(x) = 9 - 6x a. f(-2) b. f(15) c. f(1/2)

Solution

To evaluate the function f(x)=96xf(x) = 9 - 6x for specific values of xx, we substitute the given values of xx into the function and simplify.

  1. Evaluate f(2)f(-2): f(2)=96(2)=9+12=21f(-2) = 9 - 6(-2) = 9 + 12 = 21

  2. Evaluate f(15)f(15): f(15)=96(15)=990=81f(15) = 9 - 6(15) = 9 - 90 = -81

  3. Evaluate f(12)f\left(\frac{1}{2}\right): f(12)=96(12)=93=6f\left(\frac{1}{2}\right) = 9 - 6\left(\frac{1}{2}\right) = 9 - 3 = 6

So, the evaluations are:

  • f(2)=21f(-2) = 21
  • f(15)=81f(15) = -81
  • f(12)=6f\left(\frac{1}{2}\right) = 6

Would you like further details or have any questions?

Here are 8 related questions to expand on this information:

  1. How do you evaluate a function at a given point?
  2. What is the result of evaluating f(x)=96xf(x) = 9 - 6x at x=0x = 0?
  3. How can evaluating functions at different points help in understanding their behavior?
  4. What happens to f(x)=96xf(x) = 9 - 6x as xx approaches positive infinity?
  5. What happens to f(x)=96xf(x) = 9 - 6x as xx approaches negative infinity?
  6. How would you find the value of xx for which f(x)=0f(x) = 0?
  7. How does the value of the function change with increasing or decreasing xx?
  8. What is the significance of evaluating a function at fractional values of xx?

Tip: When evaluating functions at specific points, double-check your arithmetic to ensure accuracy.

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Math Problem Analysis

Mathematical Concepts

Linear Functions
Function Evaluation

Formulas

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Theorems

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Suitable Grade Level

Grades 7-9