To solve for \( x \) in the equation \( u = 2x - 2 \), follow these steps:

1. Start with the equation:
   \[
   u = 2x - 2
   \]

2. Add 2 to both sides to isolate the term with \( x \):
   \[
   u + 2 = 2x
   \]

3. Divide both sides by 2 to solve for \( x \):
   \[
   x = \frac{u + 2}{2}
   \]

Thus, the solution is:
\[
x = \frac{u + 2}{2}
\]

Would you like more details or further explanation?

Here are 5 related questions:
1. How would the solution change if the equation were \( u = 3x - 5 \)?
2. What happens if \( u = 0 \)? What is \( x \) in that case?
3. How can you verify that \( x = \frac{u + 2}{2} \) is correct by substituting values?
4. How does this approach work if the equation involves fractions, like \( u = \frac{3}{2}x - 2 \)?
5. What if the equation had an additional variable term, such as \( u = 2x - 2 + y \)?

**Tip**: When solving equations, always perform inverse operations step by step to isolate the variable.

Learn how to solve the linear equation u = 2x - 2 for x, using inverse operations to isolate the variable. This solution breaks down each step clearly and is suitable for students in Grades 6-8 who are studying algebra and linear equations.

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