To solve for \( x \) in the equation \( u = 6x + 8 - 4y \), follow these steps:

### 1. Rearrange the equation to isolate the term with \( x \):
\[
u = 6x + 8 - 4y
\]
Subtract \( 8 - 4y \) from both sides:
\[
u - 8 + 4y = 6x
\]

### 2. Solve for \( x \):
Now, divide both sides by 6:
\[
x = \frac{u - 8 + 4y}{6}
\]

So the solution for \( x \) is:
\[
x = \frac{u + 4y - 8}{6}
\]

Would you like a detailed explanation of any of these steps? Here are some related questions you might find useful:

1. How can I solve for \( y \) in this equation instead of \( x \)?
2. What happens if \( u \) and \( y \) are constants? How do you simplify further?
3. How do you apply this formula when given specific values for \( u \) and \( y \)?
4. What is the geometric interpretation of the equation when plotted on a graph?
5. How does this equation relate to systems of linear equations?

**Tip:** Always perform the same operation on both sides of an equation to maintain equality when solving for a variable.

Learn how to solve the linear equation u = 6x + 8 - 4y for x. This step-by-step guide covers key algebraic concepts, including isolating variables and applying equality properties. Suitable for students in Grades 8-10.

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