At the movie theater, child admission is $5.50 and adult admission is $8.90. On thursday, four times as many adult tickets as child tickets were sold, for a total sales of $1233.00. How many child tickets were sold that day?

Let the number of child tickets sold be $ x $. Since four times as many adult tickets as child tickets were sold, the number of adult tickets sold is $ 4x $.

The price of a child ticket is $5.50, and the price of an adult ticket is $8.90. The total revenue from the child tickets is $ 5.50x $, and the total revenue from the adult tickets is $ 8.90 \times 4x = 35.60x $.

The total sales are given as $1233.00. So, the equation for the total revenue is:

\[
5.50x + 35.60x = 1233
\]

Combining like terms:

\[
41.10x = 1233
\]

Now, solve for $ x $:

\[
x = \frac{1233}{41.10} \approx 30
\]

Thus, 30 child tickets were sold that day.

Would you like more details or have any other questions?

Here are 5 related questions:
1. How many adult tickets were sold on Thursday?
2. What would be the total revenue if 10 more child tickets were sold?
3. How would the total sales change if the price of child admission increased by $1?
4. If child tickets had been sold at half the price, how many more would need to be sold to maintain the same total revenue?
5. How much total revenue would have been generated if no child tickets were sold?

**Tip:** Always check your work by plugging the solution back into the original equation.

At the movie theater, child admission is $5.50 and adult admission is $8.90. On Thursday, four times as many adult tickets as child tickets were sold, for a total sales of $1233.00. How many child tickets were sold that day?

This detailed solution walks through solving a word problem involving ticket sales at a movie theater. The problem involves child and adult tickets, priced at $5.50 and $8.90 respectively, and asks for the number of child tickets sold given that total sales were $1233. Suitable for students in Grades 6-8.

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