To solve for $x$ when $g(x) = 0$ in the function $g(x) = -5x + 5$, follow these steps:

1. Set $g(x)$ to 0, as given: $0 = -5x + 5$

2. Solve for $x$ by isolating it on one side: $-5x = -5$

3. Divide both sides by -5: $x = 1$

Thus, the solution is: $x = 1$

Would you like further details on this solution, or do you have additional questions?

Here are some related questions for further practice:

1. What would be the value of $g(x)$ if $x = 2$?
2. If $g(x) = -5x + c$, how does the value of $x$ change when $g(x) = 0$ with different values of $c$?
3. How would the solution change if the equation were $g(x) = -3x + 5$?
4. What is the slope of the function $g(x) = -5x + 5$, and how does it affect the solution?
5. How does shifting the function $g(x) = -5x + 5$ vertically impact the point where $g(x) = 0$?

Tip: When solving linear equations, isolate the variable by performing inverse operations in the correct sequence (addition/subtraction, then multiplication/division).