To solve \(5c - 10\) for \(c = 7\), substitute \(7\) for \(c\) in the expression:

\[
5(7) - 10 = 35 - 10 = 25
\]

So, the value of \(5c - 10\) when \(c = 7\) is \(25\).

Would you like more details or have any questions?

Here are 5 related questions to expand on this concept:
1. What is the value of \(5c - 10\) when \(c = -3\)?
2. How does the expression change if we add 2 to the coefficient of \(c\)?
3. What happens if the constant \(-10\) becomes \(+10\)?
4. How would you factor the expression \(5c - 10\)?
5. Can you write a real-life scenario that can be modeled by the equation \(5c - 10\)?

**Tip:** Always substitute carefully, especially when dealing with negative numbers!

Learn how to solve the linear equation 5c - 10 by substituting the value of c = 7. This problem focuses on basic algebra and substitution techniques. Suitable for students in Grades 6-8.

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