Math Problem Statement

8=2(10+3c)

Solution

To solve the equation 8=2(10+3c)8 = 2(10 + 3c), let's follow these steps:

Step 1: Expand the equation

Distribute the 22 on the right-hand side:

8=2×10+2×3c8 = 2 \times 10 + 2 \times 3c 8=20+6c8 = 20 + 6c

Step 2: Isolate the variable term

Subtract 2020 from both sides to isolate the term with cc:

820=6c8 - 20 = 6c 12=6c-12 = 6c

Step 3: Solve for cc

Divide both sides by 66 to solve for cc:

c=126c = \frac{-12}{6} c=2c = -2

Final Answer:

c=2c = -2.

Would you like a detailed explanation of any step, or have any questions?

Here are 5 related questions:

  1. How do you solve for variables in equations with parentheses?
  2. How can you verify your solution after solving for a variable?
  3. What happens when equations include fractions or decimals?
  4. How does factoring affect the process of solving equations?
  5. How do you handle equations with multiple variables?

Tip: Always double-check your result by plugging the value of the variable back into the original equation to verify if both sides are equal.

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Math Problem Analysis

Mathematical Concepts

Algebra
Linear Equations
Distributive Property

Formulas

Distributive Property: a(b + c) = ab + ac

Theorems

Basic Linear Equation Solving

Suitable Grade Level

Grades 6-8