Math Problem Statement

2c-5=c+4

Solution

Let's solve the equation 2c5=c+42c - 5 = c + 4.

Step 1: Move all terms involving cc to one side

Subtract cc from both sides: 2c5c=c+4c2c - 5 - c = c + 4 - c This simplifies to: c5=4c - 5 = 4

Step 2: Move constant terms to the other side

Add 5 to both sides: c5+5=4+5c - 5 + 5 = 4 + 5 Simplifying this: c=9c = 9

So, the solution is c=9c = 9.

Would you like more details or have any questions?

Here are 5 related questions to explore:

  1. What happens if you have fractions in the equation?
  2. How do you handle equations with variables on both sides?
  3. What if there were more terms involving cc?
  4. How would the equation change if you had c2c^2 instead of cc?
  5. How do you solve inequalities involving similar terms?

Tip: Always check your solution by substituting it back into the original equation.

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Math Problem Analysis

Mathematical Concepts

Algebra
Linear Equations

Formulas

Basic algebraic manipulation: moving terms across the equation

Theorems

Equality property of equations
Inverse operations

Suitable Grade Level

Grades 6-8