Math Problem Statement

5(p+2)=10

Solution

Let's solve the equation 5(p+2)=105(p + 2) = 10.

Step-by-step solution:

  1. Distribute the 5 to both terms inside the parentheses: 5p+52=105p+10=105 \cdot p + 5 \cdot 2 = 10 \quad \Rightarrow \quad 5p + 10 = 10

  2. Subtract 10 from both sides to isolate the term with pp: 5p+1010=10105p=05p + 10 - 10 = 10 - 10 \quad \Rightarrow \quad 5p = 0

  3. Divide both sides by 5 to solve for pp: p=05p=0p = \frac{0}{5} \quad \Rightarrow \quad p = 0

Thus, the solution is p=0p = 0.

Would you like further details or have any questions?

Here are 5 related questions to deepen your understanding:

  1. What would happen if the equation was 5(p+3)=105(p + 3) = 10?
  2. How do we solve 3(p+4)=123(p + 4) = 12?
  3. What if the equation was 5(p2)=205(p - 2) = 20?
  4. How do we handle equations with fractions like 52(p+2)=10\frac{5}{2}(p + 2) = 10?
  5. Can we have a negative solution for pp if the equation were 5(p+2)=105(p + 2) = -10?

Tip: Always distribute multiplication across parentheses before isolating the variable to simplify equations easily.

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Math Problem Analysis

Mathematical Concepts

Algebra
Linear Equations
Distributive Property

Formulas

Distributive Property: a(b + c) = ab + ac

Theorems

Properties of Equality

Suitable Grade Level

Grades 6-8