To solve the equation \( 3x + 3 = 129 \):

1. **Subtract 3 from both sides** to isolate the term with \(x\):
   \[
   3x = 129 - 3
   \]
   \[
   3x = 126
   \]

2. **Divide both sides by 3** to solve for \(x\):
   \[
   x = \frac{126}{3}
   \]
   \[
   x = 42
   \]

So, the solution is \(x = 42\).

Would you like more details, or do you have any questions?

Here are some related questions you might find useful:

1. How would you solve \(4x + 7 = 35\)?
2. What happens if you have \(2x - 5 = 13\)?
3. How would you solve a system of equations like \(2x + 3y = 5\) and \(x - y = 2\)?
4. What if you have \(5(x + 2) = 25\)?
5. How do you solve a quadratic equation like \(x^2 + 6x + 9 = 0\)?

**Tip:** Always perform the same operation on both sides of the equation to maintain balance.

Learn how to solve the linear equation 3x + 3 = 129 with a step-by-step explanation. This problem focuses on key algebraic concepts like solving for x in a linear equation. Suitable for students in Grades 6-8.

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